Mensuration
- Each side of an equilateral triangle is 6 cm. Find its area.
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Using Rule 6, Area of the equilateral triangle =
√3 × (side)² 4 = √3 × 6 × 6 = 9√3 sq.cm. 4 Correct Option: A
Using Rule 6, Area of the equilateral triangle =
√3 × (side)² 4 = √3 × 6 × 6 = 9√3 sq.cm. 4
- If a triangle with base 8 cm has the same area as a circle with radius 8 cm, then the corresponding altitude (in cm) of the triangle is
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Using Rule 1 and 14,
Let the corresponding altitude of the triangle = x cm.
According to the question, Area of the triangle = Area of the circle⇒ 1 x × 8 = π × 8 × 8 2
⇒ x = 2 × 8 π = 16π cm.Correct Option: C
Using Rule 1 and 14,
Let the corresponding altitude of the triangle = x cm.
According to the question, Area of the triangle = Area of the circle⇒ 1 x × 8 = π × 8 × 8 2
⇒ x = 2 × 8 π = 16π cm.
- The measures (in cm) of sides of a right angled triangle are given by consecutive integers. Its area (in cm²) is
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Using Rule 1,
3² + 4² = 5²
∴ Base = 3 cm and
perpendicular = 4 cm
∴ Area of the right angled triangle= 1 × base × height 2 = 1 × 3 × 4 = 6 sq.cm. 2 Correct Option: D
Using Rule 1,
3² + 4² = 5²
∴ Base = 3 cm and
perpendicular = 4 cm
∴ Area of the right angled triangle= 1 × base × height 2 = 1 × 3 × 4 = 6 sq.cm. 2
- The area of an equilateral triangle is 4√3cm². The length of each side of the triangle is :
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Using Rule 6,
Area of the equilateral triangle= √3 × side² 4 ∴ 4√3 = √3 × side² 4 ⇒ side² = 4√3 × 4 = 16 √3
∴ Side = √16 = 4 cmCorrect Option: D
Using Rule 6,
Area of the equilateral triangle= √3 × side² 4 ∴ 4√3 = √3 × side² 4 ⇒ side² = 4√3 × 4 = 16 √3
∴ Side = √16 = 4 cm
- The length of three medians of a triangle are 9 cm, 12 cm and 15 cm. The area (in sq. cm) of the triangle is
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Using Rule 1,
AG = 6 cm.BG = 2 × 12 = 8cm. 3 GC = 2 × 15 = 10cm. 3 Area of ∆ ABG = 1 × 6 × 8 = 24sq.cm. 2
∴ Area of ∆ ABC = 3 × 24 = 72 sq. cm.Correct Option: B
Using Rule 1,
AG = 6 cm.BG = 2 × 12 = 8cm. 3 GC = 2 × 15 = 10cm. 3 Area of ∆ ABG = 1 × 6 × 8 = 24sq.cm. 2
∴ Area of ∆ ABC = 3 × 24 = 72 sq. cm.