Mensuration
-  Each side of an equilateral triangle is 6 cm. Find its area.
 
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                        View Hint View Answer Discuss in Forum Using Rule 6, Area of the equilateral triangle = √3 × (side)² 4 = √3 × 6 × 6 = 9√3 sq.cm. 4 Correct Option: AUsing Rule 6, Area of the equilateral triangle = √3 × (side)² 4 = √3 × 6 × 6 = 9√3 sq.cm. 4 
-  If a triangle with base 8 cm has the same area as a circle with radius 8 cm, then the corresponding altitude (in cm) of the triangle is
 
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                        View Hint View Answer Discuss in Forum Using Rule 1 and 14, 
 Let the corresponding altitude of the triangle = x cm.
 According to the question, Area of the triangle = Area of the circle⇒ 1 x × 8 = π × 8 × 8 2 
 ⇒ x = 2 × 8 π = 16π cm.Correct Option: CUsing Rule 1 and 14, 
 Let the corresponding altitude of the triangle = x cm.
 According to the question, Area of the triangle = Area of the circle⇒ 1 x × 8 = π × 8 × 8 2 
 ⇒ x = 2 × 8 π = 16π cm.
-  The measures (in cm) of sides of a right angled triangle are given by consecutive integers. Its area (in cm²) is
 
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                        View Hint View Answer Discuss in Forum Using Rule 1, 
 3² + 4² = 5²
 ∴ Base = 3 cm and
 perpendicular = 4 cm
 ∴ Area of the right angled triangle= 1 × base × height 2 = 1 × 3 × 4 = 6 sq.cm. 2 Correct Option: DUsing Rule 1, 
 3² + 4² = 5²
 ∴ Base = 3 cm and
 perpendicular = 4 cm
 ∴ Area of the right angled triangle= 1 × base × height 2 = 1 × 3 × 4 = 6 sq.cm. 2 
-  The area of an equilateral triangle is 4√3cm². The length of each side of the triangle is :
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                        View Hint View Answer Discuss in Forum Using Rule 6, 
 Area of the equilateral triangle= √3 × side² 4 ∴ 4√3 = √3 × side² 4 ⇒ side² = 4√3 × 4 = 16 √3 
 ∴ Side = √16 = 4 cmCorrect Option: DUsing Rule 6, 
 Area of the equilateral triangle= √3 × side² 4 ∴ 4√3 = √3 × side² 4 ⇒ side² = 4√3 × 4 = 16 √3 
 ∴ Side = √16 = 4 cm
-  The length of three medians of a triangle are 9 cm, 12 cm and 15 cm. The area (in sq. cm) of the triangle is
 
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                        View Hint View Answer Discuss in Forum Using Rule 1, 
 AG = 6 cm. BG = 2 × 12 = 8cm. 3 GC = 2 × 15 = 10cm. 3 Area of ∆ ABG = 1 × 6 × 8 = 24sq.cm. 2 
 ∴ Area of ∆ ABC = 3 × 24 = 72 sq. cm.Correct Option: BUsing Rule 1, 
 AG = 6 cm. BG = 2 × 12 = 8cm. 3 GC = 2 × 15 = 10cm. 3 Area of ∆ ABG = 1 × 6 × 8 = 24sq.cm. 2 
 ∴ Area of ∆ ABC = 3 × 24 = 72 sq. cm.
 
	