Mensuration
- The radius of the base of a right circular cone is doubled keeping its height fixed. The volume of the cone will be :
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Original volume of cone = 1 πr²h 3 New volume of cone = 1 π(2r)²h = 4 πr²h 3 3 = 4 × 1 πr²h 3
i.e. Four times of the previous volume.Correct Option: B
Original volume of cone = 1 πr²h 3 New volume of cone = 1 π(2r)²h = 4 πr²h 3 3 = 4 × 1 πr²h 3
i.e. Four times of the previous volume.
- The heights of two cones are in the ratio 1 : 3 and the diameters of their base are in the ratio 3 : 5. The ratio of their volume is
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Required ratio = 1 πr1²h1 3 = r1 ² × h1 = 3 ² × 1 1 πr²h r2 h2 5 3 3 = 3 ⇒ 3 : 25 25 Correct Option: A
Required ratio = 1 πr1²h1 3 = r1 ² × h1 = 3 ² × 1 1 πr²h r2 h2 5 3 3 = 3 ⇒ 3 : 25 25
- The base of a right circular cone has the same radius a as that of a sphere. Both the sphere and the cone have the same volume. Height of the cone is
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1 πa²h = 4 πa² 3 3
⇒ h = 4aCorrect Option: B
1 πa²h = 4 πa² 3 3
⇒ h = 4a
- The circumference of the base of a 16cm height solid cone is 33cm. What is the volume of the cone in cm³ ?
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Circumference of the base of cone = 33 cm
⇒ 2πr = 33⇒ 2 × 22 × r = 33 7 ⇒ r = 33 × 7 = 21 cm. 2 × 22 4 ∴ Volume of the cone = 1 πr²h 3 = 1 × 22 × 21 × 21 × 16 = 462 cu.cm. 3 7 4 4 Correct Option: C
Circumference of the base of cone = 33 cm
⇒ 2πr = 33⇒ 2 × 22 × r = 33 7 ⇒ r = 33 × 7 = 21 cm. 2 × 22 4 ∴ Volume of the cone = 1 πr²h 3 = 1 × 22 × 21 × 21 × 16 = 462 cu.cm. 3 7 4 4
- The perimeter of the base of a right circular cone is 8 cm. If the height of the cone is 21 cm, then its volume is:
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2πr = 8 ⇒ πr = 4
⇒ r = 4 π ∴ V = 1 πr²h - 1 π × 4 × 4 × 21 = 112 cu.cm. 3 3 π × π π Correct Option: B
2πr = 8 ⇒ πr = 4
⇒ r = 4 π ∴ V = 1 πr²h - 1 π × 4 × 4 × 21 = 112 cu.cm. 3 3 π × π π