-
The radius of the base of a right circular cone is doubled keeping its height fixed. The volume of the cone will be :
-
- three times of the previous volume
- four times of the previous volume
- √2 times of the previous volume
- double of the previous volume
- three times of the previous volume
Correct Option: B
| Original volume of cone = | πr²h | |
| 3 |
| New volume of cone = | π(2r)²h = | πr²h | ||
| 3 | 3 |
| = 4 × | πr²h | |
| 3 |
i.e. Four times of the previous volume.
