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If the radii of the circular ends of a truncated conical bucket which is 45cm high be 28 cm and 7 cm, then the capacity of the bucket in cubic centimetre is ( use π = 22/7)
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- 48510
- 45810
- 48150
- 48051
- 48510
Correct Option: A
| Volume of bucket = | πh (r1² + r2² + r1r2) | |
| 3 |
| = | × | × 45( 28² + 7² + 28 × 7) | ||
| 3 | 7 |
| = | × | × 45( 784 + 49 + 196) | ||
| 3 | 7 |
| = | × | × 45 × 1029 = 48510 cu.cm. | ||
| 3 | 7 |
