Mensuration
- The radius of base and slant height of a cone are in the ratio 4 : 7. If its curved surface area is 792 cm², then the radius (in cm) of its base is [Use π = 22/7]
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Let radius = 4x cm and slant height (l) = 7x cm
∴ πrl = 22 × 4x × 7x = 792 12 ⇒ x² = 792 × 7 = 9 22 × 4 × 7
∴ x = 3
∴ Radius = 4 × 3 = 12 cmCorrect Option: B
Let radius = 4x cm and slant height (l) = 7x cm
∴ πrl = 22 × 4x × 7x = 792 12 ⇒ x² = 792 × 7 = 9 22 × 4 × 7
∴ x = 3
∴ Radius = 4 × 3 = 12 cm
- A semi-circular sheet of metal of diameter 28 cm is bent into an open conical cup. The depth of the cup is approximately
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Length (ACB) of semi-circular sheet = πr= 22 × 14 = 44 cm. 7
Slant height of the cone = 14 cm.Circumference of the base of the cone = 2πr1 = 44 r1 7 ⇒ 44 = 44 r1 ⇒ r1 = 7 cm. 7
∴ h = √l² - r1² = √14² - 7²
= 7√3 cm. = 7 × 1.732 ≈ 12cm.Correct Option: B
Length (ACB) of semi-circular sheet = πr= 22 × 14 = 44 cm. 7
Slant height of the cone = 14 cm.Circumference of the base of the cone = 2πr1 = 44 r1 7 ⇒ 44 = 44 r1 ⇒ r1 = 7 cm. 7
∴ h = √l² - r1² = √14² - 7²
= 7√3 cm. = 7 × 1.732 ≈ 12cm.
- The area of the four walls of a room is 660 m² and its length is twice its breadth. If the height of the room is 11 m, then area of its floor (in m²) is
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Let Breadth of room = x metre Length = 2x metre
∴ Area of four walls = 2 × h (l + b)
⇒ 660 = 2 × 11 (2x + x) = 22 × 3x = 66 x⇒ x = 660 = 10 66
∴ Area of floor = 2x² = 2 × 10² = 200 sq.metreCorrect Option: C
Let Breadth of room = x metre Length = 2x metre
∴ Area of four walls = 2 × h (l + b)
⇒ 660 = 2 × 11 (2x + x) = 22 × 3x = 66 x⇒ x = 660 = 10 66
∴ Area of floor = 2x² = 2 × 10² = 200 sq.metre
- A right angled sector of radius r cm is rolled up into a cone in such a way that the two binding radii are joined together. Then the curved surface area of the cone is
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Radius of the base (r1) = r 4
Slant height = r∴ Curved surface area = πr1l = πr² cm² 4 Correct Option: C
Radius of the base (r1) = r 4
Slant height = r∴ Curved surface area = πr1l = πr² cm² 4
- The radius of the base of a conical tent is 16 metre. If 427(3/7)sq. metre canvas is required to construct the tent, then the slant height of the tent is : (Take π = 22/7)
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Curved surface area of cone = πrl
∴ 22 × 16 × l = 2992 7 7
⇒ 22 × 16 × l = 2992⇒ l = 2992 = 8.5 metre 22 × 16 Correct Option: D
Curved surface area of cone = πrl
∴ 22 × 16 × l = 2992 7 7
⇒ 22 × 16 × l = 2992⇒ l = 2992 = 8.5 metre 22 × 16