Mensuration


  1. The radius of base and slant height of a cone are in the ratio 4 : 7. If its curved surface area is 792 cm², then the radius (in cm) of its base is [Use π = 22/7]









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    Let radius = 4x cm and slant height (l) = 7x cm

    ∴ πrl =
    22
    × 4x × 7x = 792
    12

    ⇒ x² =
    792 × 7
    = 9
    22 × 4 × 7

    ∴ x = 3
    ∴ Radius = 4 × 3 = 12 cm

    Correct Option: B

    Let radius = 4x cm and slant height (l) = 7x cm

    ∴ πrl =
    22
    × 4x × 7x = 792
    12

    ⇒ x² =
    792 × 7
    = 9
    22 × 4 × 7

    ∴ x = 3
    ∴ Radius = 4 × 3 = 12 cm


  1. A semi-circular sheet of metal of diameter 28 cm is bent into an open conical cup. The depth of the cup is approximately









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    Length (ACB) of semi-circular sheet = πr

    =
    22
    × 14 = 44 cm.
    7

    Slant height of the cone = 14 cm.
    Circumference of the base of the cone = 2πr1 =
    44
    r1
    7

    ⇒ 44 =
    44
    r1 ⇒ r1 = 7 cm.
    7

    ∴ h = √l² - r1² = √14² - 7²
    = 7√3 cm. = 7 × 1.732 ≈ 12cm.

    Correct Option: B



    Length (ACB) of semi-circular sheet = πr

    =
    22
    × 14 = 44 cm.
    7

    Slant height of the cone = 14 cm.
    Circumference of the base of the cone = 2πr1 =
    44
    r1
    7

    ⇒ 44 =
    44
    r1 ⇒ r1 = 7 cm.
    7

    ∴ h = √l² - r1² = √14² - 7²
    = 7√3 cm. = 7 × 1.732 ≈ 12cm.



  1. The area of the four walls of a room is 660 m² and its length is twice its breadth. If the height of the room is 11 m, then area of its floor (in m²) is









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    Let Breadth of room = x metre Length = 2x metre
    ∴ Area of four walls = 2 × h (l + b)
    ⇒ 660 = 2 × 11 (2x + x) = 22 × 3x = 66 x

    ⇒ x =
    660
    = 10
    66

    ∴ Area of floor = 2x² = 2 × 10² = 200 sq.metre

    Correct Option: C

    Let Breadth of room = x metre Length = 2x metre
    ∴ Area of four walls = 2 × h (l + b)
    ⇒ 660 = 2 × 11 (2x + x) = 22 × 3x = 66 x

    ⇒ x =
    660
    = 10
    66

    ∴ Area of floor = 2x² = 2 × 10² = 200 sq.metre


  1. A right angled sector of radius r cm is rolled up into a cone in such a way that the two binding radii are joined together. Then the curved surface area of the cone is









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    Radius of the base (r1) =
    r
    4

    Slant height = r
    ∴ Curved surface area = πr1l =
    πr²
    cm²
    4

    Correct Option: C

    Radius of the base (r1) =
    r
    4

    Slant height = r
    ∴ Curved surface area = πr1l =
    πr²
    cm²
    4



  1. The radius of the base of a conical tent is 16 metre. If 427(3/7)sq. metre canvas is required to construct the tent, then the slant height of the tent is : (Take π = 22/7)









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    Curved surface area of cone = πrl

    22
    × 16 × l =
    2992
    77

    ⇒ 22 × 16 × l = 2992
    ⇒ l =
    2992
    = 8.5 metre
    22 × 16

    Correct Option: D

    Curved surface area of cone = πrl

    22
    × 16 × l =
    2992
    77

    ⇒ 22 × 16 × l = 2992
    ⇒ l =
    2992
    = 8.5 metre
    22 × 16