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A semi-circular sheet of metal of diameter 28 cm is bent into an open conical cup. The depth of the cup is approximately
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- 11 cm
- 12 cm
- 13 cm
- 14 cm
- 11 cm
Correct Option: B
Length (ACB) of semi-circular sheet = πr
| = | × 14 = 44 cm. | |
| 7 |
Slant height of the cone = 14 cm.
| Circumference of the base of the cone = 2πr1 = | r1 | |
| 7 |
| ⇒ 44 = | r1 ⇒ r1 = 7 cm. | |
| 7 |
∴ h = √l² - r1² = √14² - 7²
= 7√3 cm. = 7 × 1.732 ≈ 12cm.
