Mensuration


  1. If diagonal of a cube is √12 cm, then its volume in cubic cm is:









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    Diagonal of cube = √3a²
    ∴ According to question,
    3a = 2√3
    ∴ Its volume = a³ = 2³ = 8cu cm

    Correct Option: A

    Diagonal of cube = √3a²
    ∴ According to question,
    3a = 2√3
    ∴ Its volume = a³ = 2³ = 8cu cm


  1. If the volume of two cubes are in the ratio 27 : 1, the ratio of their edge is :









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    Volume of cube = (Side)³
    ∴ Ratio of volume = 27 : 1

    ∴ Ratio of the edges = 3√
    27
    1

    or 3 : 1

    Correct Option: A

    Volume of cube = (Side)³
    ∴ Ratio of volume = 27 : 1

    ∴ Ratio of the edges = 3√
    27
    1

    or 3 : 1



  1. The edges of a cuboid are in the ratio 1 : 2 : 3 and its surface area is 88cm². The volume of the cuboid is :









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    Surface area of cuboid = 2 × (l × b + b × h + h × l)
    = 2 (3x × 2x + 2x × x + x × 3x)
    = 2 (6x² + 2x² + 3x²) = 22x²
    ∴ 22x² = 88
    ⇒ x²= 4 ⇒
    ⇒ X = √4 = 2
    ∴ l = 6 cm, b = 4 cm, h = 2 cm
    ∴ Volume of cuboid = l × b × h = 6 × 4 × 2 cm³ = 48 cm³

    Correct Option: C

    Surface area of cuboid = 2 × (l × b + b × h + h × l)
    = 2 (3x × 2x + 2x × x + x × 3x)
    = 2 (6x² + 2x² + 3x²) = 22x²
    ∴ 22x² = 88
    ⇒ x²= 4 ⇒
    ⇒ X = √4 = 2
    ∴ l = 6 cm, b = 4 cm, h = 2 cm
    ∴ Volume of cuboid = l × b × h = 6 × 4 × 2 cm³ = 48 cm³


  1. If the ratio of the diameters of two right circular cones of equal height be 3 : 4, then the ratio of their volume will be









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    Ratio of the volumes of cone =
    1
    πr1²h
    3
    =
    r1
    ² =
    3
    ² ×
    9
    or 9 : 16
    1
    πr²hr2416
    3

    Correct Option: B

    Ratio of the volumes of cone =
    1
    πr1²h
    3
    =
    r1
    ² =
    3
    ² ×
    9
    or 9 : 16
    1
    πr²hr2416
    3



  1. A cuboidal water tank has 216 litres of water. Its depth is 1/3 of its length and breadth is 1/2 of 1/3 of the difference of length and breadth. The length of the tankis









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    Let the length of tank = x dm

    Depth =
    x
    dm
    3

    ⇒ Breadth = x -
    x
    ×
    1
    ×
    1
    332

    =
    2x
    ×
    1
    ×
    1
    =
    x
    dm
    3329

    ∴ Volume of tank = x ×
    x
    ×
    x
    =
    9327

    According to the question,
    = 216
    27

    ⇒ x³ = 27 × 216
    ⇒ x = (27 × 216)1/3
    ∴ x = 3 × 6 = 18 dm

    Correct Option: B

    Let the length of tank = x dm

    Depth =
    x
    dm
    3

    ⇒ Breadth = x -
    x
    ×
    1
    ×
    1
    332

    =
    2x
    ×
    1
    ×
    1
    =
    x
    dm
    3329

    ∴ Volume of tank = x ×
    x
    ×
    x
    =
    9327

    According to the question,
    = 216
    27

    ⇒ x³ = 27 × 216
    ⇒ x = (27 × 216)1/3
    ∴ x = 3 × 6 = 18 dm