Mensuration
- The wheel of a motor car makes 1000 revolutions in moving 440 m. The diameter (in metre) of the wheel is
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Using Rule 7,
Distance covered by wheel in one revolution
= Circumference of wheel= π × diameter = 440 1000 ⇒ 22 × diameter = 440 7 1000 ⇒ Diameter = 440 × 7 1000 22
= 0.14 mCorrect Option: B
Using Rule 7,
Distance covered by wheel in one revolution
= Circumference of wheel= π × diameter = 440 1000 ⇒ 22 × diameter = 440 7 1000 ⇒ Diameter = 440 × 7 1000 22
= 0.14 m
- A bicycle wheel makes 5000 revolutions in moving 11km.Then the radius of the wheel (in cm) is (Take π = 22/7 )
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Using Rule 7,
Distance covered by wheel in one revolution =Circumference of wheel = 11000 = 11 metre 5000 5 = 11 × 100 cm = 220 cm 5
∴ 2πr = 220⇒ 2 × 22 × r = 220 cm 7 ⇒ r = 220 × 7 = 35 cm 2 × 22 Correct Option: B
Using Rule 7,
Distance covered by wheel in one revolution =Circumference of wheel = 11000 = 11 metre 5000 5 = 11 × 100 cm = 220 cm 5
∴ 2πr = 220⇒ 2 × 22 × r = 220 cm 7 ⇒ r = 220 × 7 = 35 cm 2 × 22
- Three circles of diameter 10 cm each, are bound together by a rubber band, as shown in the figure.
The length of the rubber band, (in cm) if it is stretched as shown, is
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Length of the rubber band = 3d + 2πr
= (30 + 10π) cmCorrect Option: B
Length of the rubber band = 3d + 2πr
= (30 + 10π) cm
- If a chord of length 16 cm is at a distance of 15 cm from the centre of the circle, then the length of the chord of the same circle which is at a distance of 8 cm from the centre is equal to
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The chord nearer to the centre is larger.
∴ 15 = x 8 16 ⇒ x = 15 × 16 = 30 cm 8 Correct Option: C
The chord nearer to the centre is larger.
∴ 15 = x 8 16 ⇒ x = 15 × 16 = 30 cm 8
- A semicircular shaped window has diameter of 63 cm. Its perimeter equals (π = 22/7)
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Using Rule 14,
Perimeter of semi-circular shaped window
= (πr + 2r) cm = r (π + 2) cm= 63 22 + 2 cm 2 7 = 63 × 36 = 162cm 2 7 Correct Option: B
Using Rule 14,
Perimeter of semi-circular shaped window
= (πr + 2r) cm = r (π + 2) cm= 63 22 + 2 cm 2 7 = 63 × 36 = 162cm 2 7