Mensuration
-  The wheel of a motor car makes 1000 revolutions in moving 440 m. The diameter (in metre) of the wheel is
 
- 
                        View Hint View Answer Discuss in Forum Using Rule 7, 
 Distance covered by wheel in one revolution
 = Circumference of wheel= π × diameter = 440 1000 ⇒ 22 × diameter = 440 7 1000 ⇒ Diameter = 440 × 7 1000 22 
 = 0.14 mCorrect Option: BUsing Rule 7, 
 Distance covered by wheel in one revolution
 = Circumference of wheel= π × diameter = 440 1000 ⇒ 22 × diameter = 440 7 1000 ⇒ Diameter = 440 × 7 1000 22 
 = 0.14 m
-  A bicycle wheel makes 5000 revolutions in moving 11km.Then the radius of the wheel (in cm) is (Take π = 22/7 )
 
- 
                        View Hint View Answer Discuss in Forum Using Rule 7, 
 Distance covered by wheel in one revolution =Circumference of wheel = 11000 = 11 metre 5000 5 = 11 × 100 cm = 220 cm 5 
 ∴ 2πr = 220⇒ 2 × 22 × r = 220 cm 7 ⇒ r = 220 × 7 = 35 cm 2 × 22 Correct Option: BUsing Rule 7, 
 Distance covered by wheel in one revolution =Circumference of wheel = 11000 = 11 metre 5000 5 = 11 × 100 cm = 220 cm 5 
 ∴ 2πr = 220⇒ 2 × 22 × r = 220 cm 7 ⇒ r = 220 × 7 = 35 cm 2 × 22 
-  Three circles of diameter 10 cm each, are bound together by a rubber band, as shown in the figure. 
 The length of the rubber band, (in cm) if it is stretched as shown, is
 
- 
                        View Hint View Answer Discuss in Forum Length of the rubber band = 3d + 2πr 
 = (30 + 10π) cmCorrect Option: BLength of the rubber band = 3d + 2πr 
 = (30 + 10π) cm
-  If a chord of length 16 cm is at a distance of 15 cm from the centre of the circle, then the length of the chord of the same circle which is at a distance of 8 cm from the centre is equal to
 
- 
                        View Hint View Answer Discuss in Forum The chord nearer to the centre is larger. ∴ 15 = x 8 16 ⇒ x = 15 × 16 = 30 cm 8 Correct Option: CThe chord nearer to the centre is larger. ∴ 15 = x 8 16 ⇒ x = 15 × 16 = 30 cm 8 
-  A semicircular shaped window has diameter of 63 cm. Its perimeter equals (π = 22/7)
- 
                        View Hint View Answer Discuss in Forum Using Rule 14, 
 Perimeter of semi-circular shaped window
 = (πr + 2r) cm = r (π + 2) cm= 63  22 + 2  cm 2 7 = 63 × 36 = 162cm 2 7 Correct Option: BUsing Rule 14, 
 Perimeter of semi-circular shaped window
 = (πr + 2r) cm = r (π + 2) cm= 63  22 + 2  cm 2 7 = 63 × 36 = 162cm 2 7 
 
	