Mensuration
- If the side of a square is increased by 25%, then its area is increased by :
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Using Rule 12,
Let the side of a square is increased by x %, its area is increased by= 2x² + x² % 100
Here, x = 25%∴ Effective increase in area = 2 × 25 + 25 × 25 % = 56.26% 100 Correct Option: D
Using Rule 12,
Let the side of a square is increased by x %, its area is increased by= 2x² + x² % 100
Here, x = 25%∴ Effective increase in area = 2 × 25 + 25 × 25 % = 56.26% 100
- If the radius of a circle is increased by 50%, its area is increased by :
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Using Rule 12,
If the radius of circle is increased by x%, the area changes by= 2x + x² % 100 = 2 × 50 + 50 × 50 % = 125% 100 Correct Option: A
Using Rule 12,
If the radius of circle is increased by x%, the area changes by= 2x + x² % 100 = 2 × 50 + 50 × 50 % = 125% 100
- If the length of a rectangle is increased by 20% and its breadth is decreased by 20%, then its area
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Using Rule 10,
Effective change in area = x + y + xy % 100
where x and y denote percentage change= 20 - 20 - 20 × 20 % = - 4% 100
Hence, the area will decrease by 4%Correct Option: B
Using Rule 10,
Effective change in area = x + y + xy % 100
where x and y denote percentage change= 20 - 20 - 20 × 20 % = - 4% 100
Hence, the area will decrease by 4%
- If each side of a rectangle is increased by 50%, its area will be increased by
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Using Rule 10,
Effective increase = 50 + 50 + 50 × 50 % = 125% 100 Correct Option: B
Using Rule 10,
Effective increase = 50 + 50 + 50 × 50 % = 125% 100
- If the altitude of a triangle is increased by 10% while its area remains same, its corresponding base will have to be decreased by
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Let the base of triangle be decreased by x%.
According to the question,
[∵ Area remains same]10 - x - 10x = 0 100 ⇒ x + x = 10 10 ⇒ 10x + x = 10 ⇒ 11x = 10 10 10 ⇒ x = 100 = 9 1 % 11 11 Correct Option: C
Let the base of triangle be decreased by x%.
According to the question,
[∵ Area remains same]10 - x - 10x = 0 100 ⇒ x + x = 10 10 ⇒ 10x + x = 10 ⇒ 11x = 10 10 10 ⇒ x = 100 = 9 1 % 11 11