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Aptitude miscellaneous
  1. The length of the base of an isosceles triangle is 2x – 2y + 4z, and its perimeter is 4x – 2y + 6z. Then the length of each of the equal sides is








  1. View Hint View Answer Discuss in Forum

    Let each of the equal sides of isosceles triangle be a units.
    ∴ Perimeter of triangle = 2a + base
    ∴ 2a + 2x – 2y + 4z
    = 4x – 2y + 6z
    ⇒ 2a = 4x – 2y + 6z – (2x – 2y + 4z)
    = (4x – 2x) + (2y – 2y) + (6z – 4z)

    ∴ a =
    1
    		(2x + 2z) = x + y
    2

    Correct Option: D

    Let each of the equal sides of isosceles triangle be a units.
    ∴ Perimeter of triangle = 2a + base
    ∴ 2a + 2x – 2y + 4z
    = 4x – 2y + 6z
    ⇒ 2a = 4x – 2y + 6z – (2x – 2y + 4z)
    = (4x – 2x) + (2y – 2y) + (6z – 4z)

    ∴ a =
    1
    		(2x + 2z) = x + y
    2

  1. The diameter of two cylinders, whose volumes are equal, are in the ratio 3 : 2. Their heights will be in the ratio .








  1. View Hint View Answer Discuss in Forum

    d1
    		 =
    r1
    		 =
    3
    d2r22

    ∴
    πr1²h1
    		 = 1 ⇒
    9
    		 ×
    h1
    		 = 1
    πr2²h2h2

    ⇒
    h1
    		 =
    4
    		⇒ 4 : 9
    h29

    Correct Option: A

    d1
    		 =
    r1
    		 =
    3
    d2r22

    ∴
    πr1²h1
    		 = 1 ⇒
    9
    		 ×
    h1
    		 = 1
    πr2²h2h2

    ⇒
    h1
    		 =
    4
    		⇒ 4 : 9
    h29

  1. A square playground measures 1127.6164 sq. cm. If a man walks
    2
    9
    		m
    20

    a minute, the time taken by him to walk one round around it is approximately.








  1. View Hint View Answer Discuss in Forum

    Side of square field = √1127.6164 = 33.58 metre

    ∴ Perimeter of square field = (4 × 33.58) metre = 134.32 metre

    ∴ Required time =
    134.32
    		 minutes
    49
    20

    =
    134.32 × 20
    		 minutes
    49

    = 54.82 minutes

    Correct Option: B

    Side of square field = √1127.6164 = 33.58 metre

    ∴ Perimeter of square field = (4 × 33.58) metre = 134.32 metre

    ∴ Required time =
    134.32
    		 minutes
    49
    20

    =
    134.32 × 20
    		 minutes
    49

    = 54.82 minutes

  1. How many tiles, each 4 decimetre square, will be required to cover the floor of a room 8 m long and 6 m broad ?








  1. View Hint View Answer Discuss in Forum

    Area of the floor = 8 × 6 = 48 sq. m. = 4800 sq. dm.
    Area of a square tile = 4 × 4 = 16 sq. dm

    ∴ Number of tiles =
    4800
    		 = 300
    16

    Correct Option: D

    Area of the floor = 8 × 6 = 48 sq. m. = 4800 sq. dm.
    Area of a square tile = 4 × 4 = 16 sq. dm

    ∴ Number of tiles =
    4800
    		 = 300
    16

  1. The floor of a corridor is 100m long and 3 m wide. Cost of covering the floor with carpet 50 cm wide at the rate of 15 per m is








  1. View Hint View Answer Discuss in Forum

    We will need 600 m of 50cm wide carpet to cover the floor of corridor.
    ∴ Total Cost = 600×15 = 9000.

    Correct Option: B

    We will need 600 m of 50cm wide carpet to cover the floor of corridor.
    ∴ Total Cost = 600×15 = 9000.