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The length of the base of an isosceles triangle is 2x – 2y + 4z, and its perimeter is 4x – 2y + 6z. Then the length of each of the equal sides is
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- x + y
- x + y + z
- 2 (x + y)
- x + z
- x + y
Correct Option: D
Let each of the equal sides of isosceles triangle be a units.
∴ Perimeter of triangle = 2a + base
∴ 2a + 2x – 2y + 4z
= 4x – 2y + 6z
⇒ 2a = 4x – 2y + 6z – (2x – 2y + 4z)
= (4x – 2x) + (2y – 2y) + (6z – 4z)
| ∴ a = | (2x + 2z) = x + y | |
| 2 |
