Mensuration
- The diameter of the base of a right circular cone is 4 cm and its height 2√3cm. The slant height of the cone is
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Slant height of cone (l ) = √r² + h²
= √2² + (2√3)²
= √4 + 12 = √16
= 4 cmCorrect Option: B
Slant height of cone (l ) = √r² + h²
= √2² + (2√3)²
= √4 + 12 = √16
= 4 cm
- The measure of each of two opposite angles of a rhombus is 60° and the measure of one of its sides is 10cm. The length of its smaller diagonal is :
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Let AB = BC = CD = DA = 10 cm
∠BAD = ∠BCD = 60°
∴ ∠ABC = ∠ADC = 120°
and ∠CBD = ∠CDB = 60°
∴ BD = 10cmCorrect Option: A
Let AB = BC = CD = DA = 10 cm
∠BAD = ∠BCD = 60°
∴ ∠ABC = ∠ADC = 120°
and ∠CBD = ∠CDB = 60°
∴ BD = 10cm
- A right circular cone is 3.6 cm high and radius of its base is 1.6 cm. It is melted and recast into a right circular cone with radius of its base as 1.2 cm. Then the height of the cone (in cm) is
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Volume of cone = 1 πr²h 3 = π × 1.6 × 1.6 × 3.6 3
= ⇒ × 1.6 × 1.6 × 1.2 cu.cm.∴ 1 × 1.2 × 1.2 × H 3
(H is height of new cone)
= π × 1.6 × 1.6 × 1.2⇒ H = 1.6 × 1.6 × 3 = 6.4 cm 1.2 Correct Option: C
Volume of cone = 1 πr²h 3 = π × 1.6 × 1.6 × 3.6 3
= ⇒ × 1.6 × 1.6 × 1.2 cu.cm.∴ 1 × 1.2 × 1.2 × H 3
(H is height of new cone)
= π × 1.6 × 1.6 × 1.2⇒ H = 1.6 × 1.6 × 3 = 6.4 cm 1.2
- A copper sphere of radius 3 cm is beaten and drawn into a wire of diameter 0.2 cm. The length of the wire is :
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Volume of copper sphere = 4 πr³ = 4 × 22 × 3 × 3 × 3 3 3 7 = 36 × 22 cm³ 7
Radius of the wire = 0.1 cm
The wire can be treated as a solid cylinder.
Let its length be h cm.∴ π × (0.1)² × h = 36 × 22 cm³ 7 ⇒ h = 36 × 22 × 7 × 1 = 3600 cm = 36 m. 7 22 0.01
∴ Length of the wire = 36 metres.Correct Option: D
Volume of copper sphere = 4 πr³ = 4 × 22 × 3 × 3 × 3 3 3 7 = 36 × 22 cm³ 7
Radius of the wire = 0.1 cm
The wire can be treated as a solid cylinder.
Let its length be h cm.∴ π × (0.1)² × h = 36 × 22 cm³ 7 ⇒ h = 36 × 22 × 7 × 1 = 3600 cm = 36 m. 7 22 0.01
∴ Length of the wire = 36 metres.
- If surface area and volume of a sphere are S and V respectively, then value of S³/V² is
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S = 4πr², V = 4 πr³ 3 ∴ S³ = 64π³r6 V² 16 π²r6 9 = 64π × 9 = 36π 16 Correct Option: A
S = 4πr², V = 4 πr³ 3 ∴ S³ = 64π³r6 V² 16 π²r6 9 = 64π × 9 = 36π 16