Mensuration


  1. The diameter of the base of a right circular cone is 4 cm and its height 2√3cm. The slant height of the cone is









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    Slant height of cone (l ) = √r² + h²
    = √2² + (2√3
    = √4 + 12 = √16
    = 4 cm

    Correct Option: B

    Slant height of cone (l ) = √r² + h²
    = √2² + (2√3
    = √4 + 12 = √16
    = 4 cm


  1. The measure of each of two opposite angles of a rhombus is 60° and the measure of one of its sides is 10cm. The length of its smaller diagonal is :









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    Let AB = BC = CD = DA = 10 cm
    ∠BAD = ∠BCD = 60°
    ∴ ∠ABC = ∠ADC = 120°
    and ∠CBD = ∠CDB = 60°
    ∴ BD = 10cm

    Correct Option: A


    Let AB = BC = CD = DA = 10 cm
    ∠BAD = ∠BCD = 60°
    ∴ ∠ABC = ∠ADC = 120°
    and ∠CBD = ∠CDB = 60°
    ∴ BD = 10cm



  1. A right circular cone is 3.6 cm high and radius of its base is 1.6 cm. It is melted and recast into a right circular cone with radius of its base as 1.2 cm. Then the height of the cone (in cm) is









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    Volume of cone =
    1
    πr²h
    3

    =
    π
    × 1.6 × 1.6 × 3.6
    3

    = ⇒ × 1.6 × 1.6 × 1.2 cu.cm.
    1
    × 1.2 × 1.2 × H
    3

    (H is height of new cone)
    = π × 1.6 × 1.6 × 1.2
    ⇒ H =
    1.6 × 1.6 × 3
    = 6.4 cm
    1.2

    Correct Option: C

    Volume of cone =
    1
    πr²h
    3

    =
    π
    × 1.6 × 1.6 × 3.6
    3

    = ⇒ × 1.6 × 1.6 × 1.2 cu.cm.
    1
    × 1.2 × 1.2 × H
    3

    (H is height of new cone)
    = π × 1.6 × 1.6 × 1.2
    ⇒ H =
    1.6 × 1.6 × 3
    = 6.4 cm
    1.2


  1. A copper sphere of radius 3 cm is beaten and drawn into a wire of diameter 0.2 cm. The length of the wire is :









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    Volume of copper sphere =
    4
    πr³ =
    4
    ×
    22
    × 3 × 3 × 3
    337

    =
    36 × 22
    cm³
    7

    Radius of the wire = 0.1 cm
    The wire can be treated as a solid cylinder.
    Let its length be h cm.
    ∴ π × (0.1)² × h =
    36 × 22
    cm³
    7

    ⇒ h = 36 ×
    22
    ×
    7
    ×
    1
    = 3600 cm = 36 m.
    7220.01

    ∴ Length of the wire = 36 metres.

    Correct Option: D

    Volume of copper sphere =
    4
    πr³ =
    4
    ×
    22
    × 3 × 3 × 3
    337

    =
    36 × 22
    cm³
    7

    Radius of the wire = 0.1 cm
    The wire can be treated as a solid cylinder.
    Let its length be h cm.
    ∴ π × (0.1)² × h =
    36 × 22
    cm³
    7

    ⇒ h = 36 ×
    22
    ×
    7
    ×
    1
    = 3600 cm = 36 m.
    7220.01

    ∴ Length of the wire = 36 metres.



  1. If surface area and volume of a sphere are S and V respectively, then value of S³/V² is









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    S = 4πr², V =
    4
    πr³
    3

    =
    64π³r6
    16
    π²r6
    9

    =
    64π × 9
    = 36π
    16

    Correct Option: A

    S = 4πr², V =
    4
    πr³
    3

    =
    64π³r6
    16
    π²r6
    9

    =
    64π × 9
    = 36π
    16