Mensuration
- Sides of a parallelogram are in the ratio 5 : 4. Its area is 1000 sq. units. Altitude on the greater side is 20 units. Altitude on the smaller side is
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Using Rule 11,
Let the sides of parallelogram be 5x and 4x. Base × Height
= Area of parallelogram
∴ 5x × 20 = 1000⇒ x = 1000 = 10 5 × 20
⇒ Sides = 50 and 40 units
∴ 40 × h = 1000⇒ h = 1000 = 25 units 40 Correct Option: B
Using Rule 11,
Let the sides of parallelogram be 5x and 4x. Base × Height
= Area of parallelogram
∴ 5x × 20 = 1000⇒ x = 1000 = 10 5 × 20
⇒ Sides = 50 and 40 units
∴ 40 × h = 1000⇒ h = 1000 = 25 units 40
- The perimeter of a rhombus is 40 cm and the measure of an angle is 60°, then the area of it is :
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Using Rule 12,
Side = 40 = 10 cm 4
AB = AD = 10 cm
∠ABD = ∠ADB = 60°∴ Area of the rhombus = 2 × √3 × (AB)² 4 ∴ Area of the rhombus = 2 × √3 × 10 × 10 4
= 50√3 cm²Correct Option: B
Using Rule 12,
Side = 40 = 10 cm 4
AB = AD = 10 cm
∠ABD = ∠ADB = 60°∴ Area of the rhombus = 2 × √3 × (AB)² 4 ∴ Area of the rhombus = 2 × √3 × 10 × 10 4
= 50√3 cm²
- The parallel sides of a trapezium are in a ratio 2 : 3 and their shortest distance is 12 cm. If the area of the trapezium is 480 sq. cm., the longer of the parallel sides is of length :
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Using Rule 13,
Let Sides of the trapezium be 2x and 3x cm∴ 1 (2x + 3x) × 12 = 480 2 ⇒ 5x = 480 = 80 6 ⇒ x = 80 = 16 5
∴ Larger side = 3x = 16 × 3 = 48 cmCorrect Option: D
Using Rule 13,
Let Sides of the trapezium be 2x and 3x cm∴ 1 (2x + 3x) × 12 = 480 2 ⇒ 5x = 480 = 80 6 ⇒ x = 80 = 16 5
∴ Larger side = 3x = 16 × 3 = 48 cm
- If the sum of the length, breadth and height of a rectangular parallelopiped is 24 cm and the length of its diagonal is 15 cm, then its total surface area is
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l + b + h = 24 [given]
l² + b² + h² = 225 [given]
∴ (l + b + h)²
= l² + b² + h² + 2(lb + bh + hl)
⇒ (24)² = 225 + 2 (lb + bh + hl)
⇒ 2(lb + bh + hl)
= 576 – 225 = 351 sq. cm.Correct Option: D
l + b + h = 24 [given]
l² + b² + h² = 225 [given]
∴ (l + b + h)²
= l² + b² + h² + 2(lb + bh + hl)
⇒ (24)² = 225 + 2 (lb + bh + hl)
⇒ 2(lb + bh + hl)
= 576 – 225 = 351 sq. cm.
- The perimeter of a non-square rhombus is 20 cm. One of its diagonal is 8 cm. The area of the rhombus is
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Using Rule 12,
Side of rhombus = 20 = 5 cm 4
OB = 4 cm
OA = √5² - 4² = √9
= 3 cm
AC = 6 cmArea of rhombus = 1 d1d2 1 × 8 × 6 = 24 sq. cm 2 2 Correct Option: D
Using Rule 12,
Side of rhombus = 20 = 5 cm 4
OB = 4 cm
OA = √5² - 4² = √9
= 3 cm
AC = 6 cmArea of rhombus = 1 d1d2 1 × 8 × 6 = 24 sq. cm 2 2