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The perimeter of a rhombus is 40 cm and the measure of an angle is 60°, then the area of it is :
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- 100√3 cm²
- 50√3 cm²
- 160√3 cm²
- 100 cm²
- 100√3 cm²
Correct Option: B
Using Rule 12,
| Side = | = 10 cm | |
| 4 |
AB = AD = 10 cm
∠ABD = ∠ADB = 60°
| ∴ Area of the rhombus = 2 × | × (AB)² | |
| 4 |
| ∴ Area of the rhombus = 2 × | × 10 × 10 | |
| 4 |
= 50√3 cm²
