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If the height of a right circular cone is increased by 200% and the radius of the base is reduced by 50%, the volume of the
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- cone increases by 25%
- increases by 50%
- remains unaltered
- decreases by 25%
- cone increases by 25%
Correct Option: D
| Volume of original cone = | πr²h | |
| 3 |
Now, r1 = radius of new cone = r/2
h1 = height of new cone = 3h
| ∴ V1 = | πr1²h1 = | π | × 3h = | πr²h × | = | V | ||||||
| 3 | 3 | 4 | 3 | 4 | 4 |
| ∴ Decrease % = |  | V - | V |  | × 100 | |
| V | ||||||
= 25%
