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If the height and the radius of the base of a cone are each increased by 100%, then the volume of the cone becomes
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- double that of the original
- three times that of the original
- six times that of the original
- eight times that of the original
- double that of the original
Correct Option: D
For original cone,
V = | πr²h | |
3 |
For the second cone,
r1 = 2r
h1 = 2h
∴ V1 = | πr1²h1 | |
3 |
= | π(2r)² × 2h | |
3 |
= 8 × | πr²h = 8 V | |
3 |