## Introduction to Data Interpretation

#### Data Interpretation

Direction: Study the bar diagram and answer the following questions. 1. Average marks obtained in Physics for two terms is

1. On the basis of given graph in question ,
Total marks obtained in Physics for two terms = 90 + 75 = 165
Number of terms = 2

 Required average = Total marks obtained in Physics for two terms Number of terms

##### Correct Option: B

On the basis of given graph in question ,
Total marks obtained in Physics for two terms = 90 + 75 = 165
Number of terms = 2

 Required average = Total marks obtained in Physics for two terms Number of terms

 Required average = 165 = 82.5 2

Direction: The following figure shows the number of students (in thousands) admitted and passed out per year in a college during years 2000 to 2004. Study the figure and answer the questions. 1. The ratio of the number of students admitted in the year 2002 to the average of the number of students passed out in the years 2003 and 2004. is

1. According to given bar graph , we have
Number of students admitted in the year 2002 = 8 thousands
Total number of students passed out in the years 2003 and 2004 = 9 + 9 = 18 thousands
Number of given years = 2
Required ratio = Number of students admitted in the year 2002 : Average of the number of students passed out in the years 2003 and 2004

##### Correct Option: B

According to given bar graph , we have
Number of students admitted in the year 2002 = 8 thousands
Total number of students passed out in the years 2003 and 2004 = 9 + 9 = 18 thousands
Number of given years = 2
Required ratio = Number of students admitted in the year 2002 : Average of the number of students passed out in the years 2003 and 2004

 Required ratio = 8 : 18 2

Required ratio = 8 : 9

1. In which of the two years, the pass percentage of students was between 60 and 70?

1. On the basis of given graph in question ,
Number of passed student in 2000 = 4 thousands
Number of admitted student in 2000 = 6 thousands

 Passing percentage in 2000 = 4 × 100 6

 Passing percentage in 2000 = 200 = 66 2 % 3 3

Number of passed student in 2001 = 6 thousands
Number of admitted student in 2001 = 9 thousands

##### Correct Option: A

On the basis of given graph in question ,
Number of passed student in 2000 = 4 thousands
Number of admitted student in 2000 = 6 thousands

 Passing percentage in 2000 = 4 × 100 6

 Passing percentage in 2000 = 200 = 66 2 % 3 3

Number of passed student in 2001 = 6 thousands
Number of admitted student in 2001 = 9 thousands
 Passing percentage in 2001 = 6 × 100 = 200 = 66 2 % 9 3 3

1. During 2000 to 2003, the ratio of the total number of the students passed out to the total number of students admitted is

1. As per the given bar graph , we have
During 2000 to 2003,
Total students admitted = (6 + 9 + 8 + 12) thousands = 35 thousands
Total students passed = (4 + 6 + 6 + 9) thousands = 25 thouseands
∴ Required ratio = Total students passed : Total students admitted

##### Correct Option: D

As per the given bar graph , we have
During 2000 to 2003,
Total students admitted = (6 + 9 + 8 + 12) thousands = 35 thousands
Total students passed = (4 + 6 + 6 + 9) thousands = 25 thouseands
∴ Required ratio = Total students passed : Total students admitted
Required ratio = 25 : 35 = 5 : 7

1. The percent increase in the number of students admitted in the year 2003 over that in 2001 is

1. According to given bar graph , we have
Number of students admitted in 2001 = 9000
Number of students admitted in 2003 = 12000
Increase = 12000 - 9000 = 3000

 Percentage increase = Increase × 100 Number of students admitted in 2001

##### Correct Option: B

According to given bar graph , we have
Number of students admitted in 2001 = 9000
Number of students admitted in 2003 = 12000
Increase = 12000 - 9000 = 3000

 Percentage increase = Increase × 100 Number of students admitted in 2001

 Percentage increase = 100 % = 33.3% 3