Introduction to Data Interpretation
Direction: Following histogram depicts the range of heights of students in a class of 60 students. Study the same and answer the questions.
 The number of students with their heights between 130 to 150 cms is

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According to given bar graph , we have
The number of students having height interval 130140 = 6
The number of students having height interval 140150 = 8
Required number of students = The number of students having height interval 130140 + The number of students having height interval 140150Correct Option: C
According to given bar graph , we have
The number of students having height interval 130140 = 6
The number of students having height interval 140150 = 8
Required number of students = The number of students having height interval 130140 + The number of students having height interval 140150
Required number of students = 6 + 8 = 14
 The number of students having height more than 150 cms is

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On the basis of given graph in question ,
The number of students having height interval 150160 = 25
The number of students having height interval 160170 = 7
The number of students having height interval 170180 = 4
The number of students having height interval 180190 = 2Correct Option: C
On the basis of given graph in question ,
The number of students having height interval 150160 = 25
The number of students having height interval 160170 = 7
The number of students having height interval 170180 = 4
The number of students having height interval 180190 = 2
Required number of students = 25 + 7 + 4 + 2 = 38
Direction: The histogram, given below, shows the number of families of a locality having various daily incomes, as obtained by a survey. Observe the graph and answer the questions based on it.
 What percent of families have their daily incomes less than $ 500?

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As per the given above bar graph , we have
Number of families who have daily income interval 0100 = 15
Number of families who have daily income interval 100200 = 10
Number of families who have daily income interval 200300 = 40
Number of families who have daily income interval 300400 = 5
Number of families who have daily income interval 400500 = 20
Number of families who have daily incomes less than $ 500 = 15 + 10 + 40 + 5 + 20 = 90
Total number of families = 15 + 10 + 40 + 5 + 20 + 30 + 15 + 10 + 40 + 15 = 200Correct Option: B
As per the given above bar graph , we have
Number of families who have daily income interval 0100 = 15
Number of families who have daily income interval 100200 = 10
Number of families who have daily income interval 200300 = 40
Number of families who have daily income interval 300400 = 5
Number of families who have daily income interval 400500 = 20
Number of families who have daily incomes less than $ 500 = 15 + 10 + 40 + 5 + 20 = 90
Total number of families = 15 + 10 + 40 + 5 + 20 + 30 + 15 + 10 + 40 + 15 = 200Required percentage = 90 × 100 = 45% 200
 The number of families, whose daily incomes are between $ 500 and $ 800, is

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On the basis of given graph in question ,
Number of families in daily income interval 500600 = 30
Number of families in daily income interval 600700 = 15
Number of families in daily income interval 700800 = 10
Required answer = Number of families in daily income interval 500600 + Number of families in daily income interval 600700 + Number of families in daily income interval 700800Correct Option: D
On the basis of given graph in question ,
Number of families in daily income interval 500600 = 30
Number of families in daily income interval 600700 = 15
Number of families in daily income interval 700800 = 10
Required answer = Number of families in daily income interval 500600 + Number of families in daily income interval 600700 + Number of families in daily income interval 700800
Required answer = 55
 The number of families, whose daily incomes are below $ 200, is

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As per the given above bar graph , we can see
Number of families in daily income interval 0100 = 15
Number of families in daily income interval 100200 = 10Correct Option: A
As per the given above bar graph , we can see
Number of families in daily income interval 0100 = 15
Number of families in daily income interval 100200 = 10
Required number of families = 15 + 10 = 25