Introduction to Data Interpretation
Direction: The bar graph given here shows the number of job- seekers of a state in various years at different stages of education. Study the graph carefully and answer the questions based on it.

- In comparison to the year 1973, how many more job-seekers in all, were there in the year 1977?
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According to given bar graph , we have
→ Year 1973 , Number of job-seekers = 1625
→ Year 1977 , Number of job-seekers = 4000
Required difference = Number of job-seekers in 1977 - Number of job-seekers in 1973Correct Option: C
According to given bar graph , we have
→ Year 1973 , Number of job-seekers = 1625
→ Year 1977 , Number of job-seekers = 4000
Required difference = Number of job-seekers in 1977 - Number of job-seekers in 1973
∴ Required difference = 4000 – 1625 = 2375
- In which year was the number of Graduate job-seekers the same as that of Senior Secondary job- seekers?
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On the basis of given graph in question ,
Number of Graduate job- seekers in 1974 = 525
Total number of Graduate and Senior secondary job- seekers in 1974 = 1050Correct Option: B
On the basis of given graph in question ,
Number of Graduate job- seekers in 1974 = 525
Total number of Graduate and Senior secondary job- seekers in 1974 = 1050
∴ Number of Senior secondary job -seekers in 1974 = 1050 – 525 = 525
Direction: The following is a horizontal bar diagram showing the accidents in which two-wheelers are involved with other objects. Study the diagram and answer the questions.

- The percentage by which the accidents involving buses is less than the accidents involving tanker lorry is
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From the given bar diagram , we see that one box represents a number of 20 units.
Number of the accidents involving buses = 6 boxes = 6 × 20 = 120 units
Number of the accidents involving tanker lorry = 8 boxes = 8 × 20 = 160 units
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 unitsCorrect Option: B
From the given bar diagram , we see that one box represents a number of 20 units.
Number of the accidents involving buses = 6 boxes = 6 × 20 = 120 units
Number of the accidents involving tanker lorry = 8 boxes = 8 × 20 = 160 units
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 unitsRequired difference = 160 - 120 × 100 = 4% 1000
- The percentage of accidents in which pedestrians and cyclists are involved is
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As per the given bar diagram , we see that one box represents a number of 20 units.
Number of the accidents involving pedestrians = 2 boxes = 2 × 20 = 40 units
Number of the accidents involving cyclists = 10 boxes = 10 × 20 = 200 units
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 unitsRequired percentage = 40 + 200 × 100 1000
Correct Option: A
As per the given bar diagram , we see that one box represents a number of 20 units.
Number of the accidents involving pedestrians = 2 boxes = 2 × 20 = 40 units
Number of the accidents involving cyclists = 10 boxes = 10 × 20 = 200 units
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 unitsRequired percentage = 40 + 200 × 100 1000 Required percentage = 24000 = 24% 1000
- If the data of the bar diagram is represented by a pie-chart, and the angle of a sector of the pie- chart is 36°, then this sector represents the accidents involving
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On the basis of given graph in question , we see that one box represents a number of 20 units.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 units
In pie chart , complete angle = 360°
∵ 1000 ≡ 360°∴ 100 ≡ 360 × 100 = 36° 1000
Correct Option: D
On the basis of given graph in question , we see that one box represents a number of 20 units.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 units
In pie chart , complete angle = 360°
∵ 1000 ≡ 360°∴ 100 ≡ 360 × 100 = 36° 1000
From above clear that this sector represents the accidents involving stationary vehicles .
So , stationary vehicles having in diagram = 5 Boxes = 5 × 20 = 100 units
Hence , required answer is option D .