Introduction to Data Interpretation
Direction: The bar graph given here shows the number of job seekers of a state in various years at different stages of education. Study the graph carefully and answer the questions based on it.
 In comparison to the year 1973, how many more jobseekers in all, were there in the year 1977?

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According to given bar graph , we have
→ Year 1973 , Number of jobseekers = 1625
→ Year 1977 , Number of jobseekers = 4000
Required difference = Number of jobseekers in 1977  Number of jobseekers in 1973Correct Option: C
According to given bar graph , we have
→ Year 1973 , Number of jobseekers = 1625
→ Year 1977 , Number of jobseekers = 4000
Required difference = Number of jobseekers in 1977  Number of jobseekers in 1973
∴ Required difference = 4000 – 1625 = 2375
 In which year was the number of Graduate jobseekers the same as that of Senior Secondary job seekers?

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On the basis of given graph in question ,
Number of Graduate job seekers in 1974 = 525
Total number of Graduate and Senior secondary job seekers in 1974 = 1050Correct Option: B
On the basis of given graph in question ,
Number of Graduate job seekers in 1974 = 525
Total number of Graduate and Senior secondary job seekers in 1974 = 1050
∴ Number of Senior secondary job seekers in 1974 = 1050 – 525 = 525
Direction: The following is a horizontal bar diagram showing the accidents in which twowheelers are involved with other objects. Study the diagram and answer the questions.
 The percentage by which the accidents involving buses is less than the accidents involving tanker lorry is

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From the given bar diagram , we see that one box represents a number of 20 units.
Number of the accidents involving buses = 6 boxes = 6 × 20 = 120 units
Number of the accidents involving tanker lorry = 8 boxes = 8 × 20 = 160 units
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 unitsCorrect Option: B
From the given bar diagram , we see that one box represents a number of 20 units.
Number of the accidents involving buses = 6 boxes = 6 × 20 = 120 units
Number of the accidents involving tanker lorry = 8 boxes = 8 × 20 = 160 units
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 unitsRequired difference = 160  120 × 100 = 4% 1000
 The percentage of accidents in which pedestrians and cyclists are involved is

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As per the given bar diagram , we see that one box represents a number of 20 units.
Number of the accidents involving pedestrians = 2 boxes = 2 × 20 = 40 units
Number of the accidents involving cyclists = 10 boxes = 10 × 20 = 200 units
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 unitsRequired percentage = 40 + 200 × 100 1000
Correct Option: A
As per the given bar diagram , we see that one box represents a number of 20 units.
Number of the accidents involving pedestrians = 2 boxes = 2 × 20 = 40 units
Number of the accidents involving cyclists = 10 boxes = 10 × 20 = 200 units
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 unitsRequired percentage = 40 + 200 × 100 1000 Required percentage = 24000 = 24% 1000
 If the data of the bar diagram is represented by a piechart, and the angle of a sector of the pie chart is 36°, then this sector represents the accidents involving

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On the basis of given graph in question , we see that one box represents a number of 20 units.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 units
In pie chart , complete angle = 360°
∵ 1000 ≡ 360°∴ 100 ≡ 360 × 100 = 36° 1000
Correct Option: D
On the basis of given graph in question , we see that one box represents a number of 20 units.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 units
In pie chart , complete angle = 360°
∵ 1000 ≡ 360°∴ 100 ≡ 360 × 100 = 36° 1000
From above clear that this sector represents the accidents involving stationary vehicles .
So , stationary vehicles having in diagram = 5 Boxes = 5 × 20 = 100 units
Hence , required answer is option D .