Introduction to Data Interpretation
Direction: Study the following Bar graph and answer the questions. The Bar Graph gives the annual rates of inflation in percentages for 1975 and 1987.
 From 1975 to 1987, inflation rate increased in the third world countries approximately by

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On the basis of given graph in question ,
Inflation rate of the third world in 1987 = 36.2
Inflation rate of the third world in 1975 = 26.6
Increase in rate = 36.2  26.6 = 9.6Required percentage increase = Increase in rate × 100 Inflation rate of the third world in 1975
Correct Option: D
On the basis of given graph in question ,
Inflation rate of the third world in 1987 = 36.2
Inflation rate of the third world in 1975 = 26.6
Increase in rate = 36.2  26.6 = 9.6Required percentage increase = Increase in rate × 100 Inflation rate of the third world in 1975 Required percentage increase = 9.6 × 100 ≈ 36% 26.6
Direction: Study the bar diagram and answer the following questions.
 The ratio of the average of the marks obtained in Biology for two terms to the average of the marks obtained in English and Mathematics for first term only is

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According to given bar graph , we have
Total marks obtained in Biology for two terms = 85 + 60 = 145
Total marks obtained in English and Mathematics for first term = 70 + 100 = 170
Required ratio = average of the marks obtained in Biology for two terms : average of the marks obtained in English and Mathematics for first termCorrect Option: C
According to given bar graph , we have
Total marks obtained in Biology for two terms = 85 + 60 = 145
Total marks obtained in English and Mathematics for first term = 70 + 100 = 170
Required ratio = average of the marks obtained in Biology for two terms : average of the marks obtained in English and Mathematics for first termRequired ratio = 85 + 60 = 70 + 100 = 145 : 170 = 29 : 34 2 2
 What is the percentage of marks obtained in Chemistry for both the terms?

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From the given bar diagram , we see
Total marks obtained in Chemistry for both the terms = 70 + 65 = 135Required percent = Total marks obtained in Chemistry for both the terms × 100 200
Correct Option: D
From the given bar diagram , we see
Total marks obtained in Chemistry for both the terms = 70 + 65 = 135Required percent = Total marks obtained in Chemistry for both the terms × 100 200 Required percent = 135 = 67.5 2
 Difference of marks obtained in both the terms by the students is maximum in

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According to given bar graph , we have
Difference between the marks in Biology = 85 – 60 = 25
Difference between the marks in Maths = 100 – 80 = 20
Difference between the marks in Physics = 90 – 75 = 15Correct Option: C
According to given bar graph , we have
Difference between the marks in Biology = 85 – 60 = 25
Difference between the marks in Maths = 100 – 80 = 20
Difference between the marks in Physics = 90 – 75 = 15
Hence , required answer is Biology .
 Average marks obtained in Physics for two terms is

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On the basis of given graph in question ,
Total marks obtained in Physics for two terms = 90 + 75 = 165
Number of terms = 2Required average = Total marks obtained in Physics for two terms Number of terms
Correct Option: B
On the basis of given graph in question ,
Total marks obtained in Physics for two terms = 90 + 75 = 165
Number of terms = 2Required average = Total marks obtained in Physics for two terms Number of terms Required average = 165 = 82.5 2