## Introduction to Data Interpretation

#### Data Interpretation

Direction: Study the bar diagram and answer the questions.

1. The average number of boys from all the departments together is

1. From the given bar diagram , we see
Total number of boys from all the departments = 60 + 200 + 100 + 160 + 120 = 660
Number of departments = 5

 Average number of boys = 660 5

##### Correct Option: B

From the given bar diagram , we see
Total number of boys from all the departments = 60 + 200 + 100 + 160 + 120 = 660
Number of departments = 5

 Average number of boys = 660 = 132 5

1. The difference between the total number of boys and the total number of girls from all the Departments together is

1. As per the given bar graph , we have
Total number of boys = 60 + 220 + 100 + 160 + 120 = 660
Total number of girls = 1100
Required difference = Total number of girls - Total number of boys

##### Correct Option: D

As per the given bar graph , we have
Total number of boys = 60 + 220 + 100 + 160 + 120 = 660
Total number of girls = 1100
Required difference = Total number of girls - Total number of boys
Required difference = 1100 – 660 = 440

1. The percentage of the girls from Biology Department compared to the total number of girls from all the other Departments together is

1. As per the given bar graph , we have
Girls in Biology = 300
Girls in all other departments = 140 + 180 + 260 + 220 = 800

 ∴ Required percentage = 300 × 100 800

##### Correct Option: A

As per the given bar graph , we have
Girls in Biology = 300
Girls in all other departments = 140 + 180 + 260 + 220 = 800

 ∴ Required percentage = 300 × 100 800

 Required percentage = 75 = 37 1 % 2 2

Direction: Sales of Books (in thousand numbers) from Six Branches – B1, B2, B3, B4, B5 and B6 of a publishing Company in 2000 and 2001. Study the graph and answer the questions.

1. Find the percentage increase in the sales of books of branch B3 in the year 2001 than the branch B2.

1. From the given bar diagram , we see
The sales of books of branch B3 in the year 2001 = 110 thousands
The sales of books of branch B2 in the year 2001 = 65 thousands

 Required percentage = (110 - 65) × 100 65

##### Correct Option: A

From the given bar diagram , we see
The sales of books of branch B3 in the year 2001 = 110 thousands
The sales of books of branch B2 in the year 2001 = 65 thousands

 Required percentage = (110 - 65) × 100 65

 Required percentage = 45 × 100 = 69.2% 65

1. The average sale of branches B1, B3 and B6 in 2000 is what percent of the average sale of branches B1, B2 and B3 in 2000?

1. As per the given bar graph , we have
Total sale of branches B1, B2 and B3 in 2001 = 105 +65 + 110 = 280 thousands
Number of given branches = 3

 Average sale of branches B1, B2 and B3 in 2001 = 105 +65 + 110 3

 Average sale of branches B1, B2 and B3 in 2001 = 280 thousand 3

Total sale of branches B1, B3 and B6 in 2000 = 80 + 95 + 70 = 245 thousands
Number of given branches = 3
 Average sale of branches B1, B3 and B6 in 2000 = 80 + 95 + 70 Thousand 3

 Average sale of branches B1, B3 and B6 in 2000 = 245 Thousand 3

##### Correct Option: A

As per the given bar graph , we have
Total sale of branches B1, B2 and B3 in 2001 = 105 +65 + 110 = 280 thousands
Number of given branches = 3

 Average sale of branches B1, B2 and B3 in 2001 = 105 +65 + 110 3

 Average sale of branches B1, B2 and B3 in 2001 = 280 thousand 3

Total sale of branches B1, B3 and B6 in 2000 = 80 + 95 + 70 = 245 thousands
Number of given branches = 3
 Average sale of branches B1, B3 and B6 in 2000 = 80 + 95 + 70 Thousand 3

 Average sale of branches B1, B3 and B6 in 2000 = 245 Thousand 3

 ∴ Required percentage = 81.66 × 100 93.33

 Required percentage = 24500 = 87.5% 280