Introduction to Data Interpretation
Direction: The table given below depicts the export of a commodity through four ports in the years 1998 and 1999.
- What was the change in the aggregate export of the commodity in the year 1999 as compared to the year 1998?
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View Hint View Answer Discuss in Forum
On the basis of given table in question ,
Aggregate export in 1998 = $ (57 + 148 + 229 + 146) crore = $ 580 crore
Aggregate export in 1999 = $ (61 + 160 + 234 + 150) crore
Aggregate export in 1999 = $ 605 crore
Increase = $ (605 – 580) crore = $ 25 crore∴ Percentage increase = Increase × 100 Aggregate export in 1998
Correct Option: A
On the basis of given table in question ,
Aggregate export in 1998 = $ (57 + 148 + 229 + 146) crore = $ 580 crore
Aggregate export in 1999 = $ (61 + 160 + 234 + 150) crore
Aggregate export in 1999 = $ 605 crore
Increase = $ (605 – 580) crore = $ 25 crore∴ Percentage increase = Increase × 100 Aggregate export in 1998 Percentage increase = 25 × 100 = 4.3% 580
- The percentage increase in the export of the commodity from the year 1998 to 1999 was the highest from which port?
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View Hint View Answer Discuss in Forum
According to given table, we have
Export of Port A in 1998 = 57 crore rupees
Export of Port A in 1999 = 61 crore rupees
Increase = 61 - 57 = 4 crore rupeesPercentage increase in Port A → 4 × 100 = 7% 57
Export of Port B in 1998 = 148 crore rupees
Export of Port B in 1999 = 160 crore rupees
Increase = 160 - 148 = 12 crore rupeesPercentage increase in Port B → 12 × 100 = 8.1% 148
Export of Port C in 1998 = 229 crore rupees
Export of Port C in 1999 = 234 crore rupees
Increase = 234 - 229 = 5 crore rupees
Correct Option: B
According to given table, we have
Export of Port A in 1998 = 57 crore rupees
Export of Port A in 1999 = 61 crore rupees
Increase = 61 - 57 = 4 crore rupeesPercentage increase in Port A → 4 × 100 = 7% 57
Export of Port B in 1998 = 148 crore rupees
Export of Port B in 1999 = 160 crore rupees
Increase = 160 - 148 = 12 crore rupeesPercentage increase in Port B → 12 × 100 = 8.1% 148
Export of Port C in 1998 = 229 crore rupees
Export of Port C in 1999 = 234 crore rupees
Increase = 234 - 229 = 5 crore rupeesPercentage increase in Port C → 5 × 100 = 2.2% 229
Export of Port D in 1998 = 146 crore rupees
Export of Port D in 1999 = 150 crore rupees
Increase = 150 - 146 = 4 crore rupeesPercentage increase in Port D → 4 × 100 = 2.74% 146
From above it is clear that Export form B is highest.
Direction: Study the table and answer the questions:
The table given below shows the highest and average marks of a class in four subjects in four years. The maximum marks in each subject are 100.
- In which year, the difference between the highest and average marks in Social Science was the least?
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View Hint View Answer Discuss in Forum
According to given table, we have
It was in the year 1994.
Highest marks = 66
Average marks = 58
∴ Required Difference = Highest marks – Average marksCorrect Option: C
According to given table, we have
It was in the year 1994.
Highest marks = 66
Average marks = 58
∴ Required Difference = Highest marks – Average marks
Difference = 66 – 58 = 8
- In which year, the difference between the highest and the average marks in Mathematics was maximum?
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View Hint View Answer Discuss in Forum
As per the given above table , we can see
It was maximum in the year 1993.
Highest marks = 94
Average marks = 60
Required difference = Highest marks - Average marksCorrect Option: B
As per the given above table , we can see
It was maximum in the year 1993.
Highest marks = 94
Average marks = 60
Required difference = Highest marks - Average marks
∴ Required difference = 94 – 60 = 34
- Supposing that there were 40 students in science in the year 1995, how much total of marks did they receive combined together?
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View Hint View Answer Discuss in Forum
On the basis of given table in question ,
Average marks of science in 1995 = 68
Number of students in science in the year 1995 = 40
Total marks = Average marks of science in 1995 × Number of students in scienceCorrect Option: B
On the basis of given table in question ,
Average marks of science in 1995 = 68
Number of students in science in the year 1995 = 40
Total marks = Average marks of science in 1995 × Number of students in science
∴ Total marks = 68 × 40 = 2720
