Introduction to Data Interpretation
Direction: Study the following bar graph carefully and answer the questions.
 The tuition fee at State University in the year 2000 was Rs. 6500 per enrolment. What was the total revenue collected from the tuition fee at State University during that year?

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As per the given bar graph , we have
Total enrollments at State University in the year 2000 = 12000
Tuition fee per enrolment = Rs. 6500
Required total collected amount as fees = Total enrollments at State University × Tuition fee per enrolmentCorrect Option: B
As per the given bar graph , we have
Total enrollments at State University in the year 2000 = 12000
Tuition fee per enrolment = Rs. 6500
Required total collected amount as fees = Total enrollments at State University × Tuition fee per enrolment
Required total collected amount as fees = Rs. (12000 × 6500) = Rs. 78000000
 The ratio of the total enrollments in the year 1980 and 2000 at the State University and Central University is

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On the basis of given graph in question ,
Total enrollments in the year 1980 and 2000 at the State University = 8000 + 12000 = 20000
Total enrollments in the year 1980 and 2000 at the Central University = 10000 + 14000 = 24000Correct Option: D
On the basis of given graph in question ,
Total enrollments in the year 1980 and 2000 at the State University = 8000 + 12000 = 20000
Total enrollments in the year 1980 and 2000 at the Central University = 10000 + 14000 = 24000
Required ratio = 20000 : 24000
Hence , Required ratio = 20 : 24 = 5 : 6
 Total enrollments in both State University and Central University during the year 1980, 1990 and 2000 is

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According to given bar diagram , we see
Number of students were enrolled at State and Central University in 1980 = 8000 + 10000 = 18000
Number of students were enrolled at State and Central University in 1990 = 14000 + 12000 = 26000
Number of students were enrolled at State and Central University in 2000 = 12000 + 14000 = 26000Correct Option: C
According to given bar diagram , we see
Number of students were enrolled at State and Central University in 1980 = 8000 + 10000 = 18000
Number of students were enrolled at State and Central University in 1990 = 14000 + 12000 = 26000
Number of students were enrolled at State and Central University in 2000 = 12000 + 14000 = 26000
Required total enrollment = (18000 + 26000 + 26000) = 70000
 In 1990, how many more students were enrolled at State University than at Central University?

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From the given bar diagram , we see
Number of students were enrolled at State University in 1990 = 14000
Number of students were enrolled at Central University in 1990 = 12000
Required answer = Number of students were enrolled at State University in 1990  Number of students were enrolled at Central University in 1990Correct Option: C
From the given bar diagram , we see
Number of students were enrolled at State University in 1990 = 14000
Number of students were enrolled at Central University in 1990 = 12000
Required answer = Number of students were enrolled at State University in 1990  Number of students were enrolled at Central University in 1990
Required answer = 14000 – 12000 = 2000
Direction: The Bar graphs represents the number of road accidents due to bus and car during the years 2008 2013. Study the graph and answer the questions.
 The ratio of the averages of the road accidents due to buses to that by cars in the year 2008, 2011 and 2013 is

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As per the given bar graph , we have
Total number of the road accidents by buses in the year 2008, 2011 and 2013 = 30 + 60 + 10 = 100
Total number of the road accidents by cars in the year 2008, 2011 and 2013 = 40 + 20+ 20 = 80
Number of given years = 3Required ratio = Total number of the road accidents by buses : Total number of the road accidents by cars 3 3
Required ratio = 100 : 80 = 5 : 4Correct Option: B
As per the given bar graph , we have
Total number of the road accidents by buses in the year 2008, 2011 and 2013 = 30 + 60 + 10 = 100
Total number of the road accidents by cars in the year 2008, 2011 and 2013 = 40 + 20+ 20 = 80
Number of given years = 3Required ratio = Total number of the road accidents by buses : Total number of the road accidents by cars 3 3
Required ratio = 100 : 80 = 5 : 4