Introduction to Data Interpretation
Direction: The distribution of fruit consumption in a sample of 72 seventeen  year  old girls is given in the graph below. Study the graph and answer the questions.
 What percent of these girls ate six or more servings per day?

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As per the given bar graph , we have
Number of girls who ate six or more servings per day = 3 + 3 + 3 = 9
Total number of girls = 72∴ Required percentage = Number of girls who ate six or more servings per day × 100 Total number of girls
Correct Option: A
As per the given bar graph , we have
Number of girls who ate six or more servings per day = 3 + 3 + 3 = 9
Total number of girls = 72∴ Required percentage = Number of girls who ate six or more servings per day × 100 Total number of girls ∴ Required percentage = 9 × 100 = 25 = 12.5% 72 2
 How many of these girls ate fewer than two servings per day?

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On the basis of given graph in question ,
Number of girls ate 2 servings per day = 15
Number of girls ate 1 servings per day = 10
Required number of girls = Number of girls ate 2 servings per day + Number of girls ate 1 servings per dayCorrect Option: C
On the basis of given graph in question ,
Number of girls ate 2 servings per day = 15
Number of girls ate 1 servings per day = 10
Required number of girls = Number of girls ate 2 servings per day + Number of girls ate 1 servings per day
Required number of girls = 15 + 10 = 25
Therefore , Required number of girls is 25 .
Direction: The bar graph shows the marks obtained by a student in an examination out of 100 marks in each subject. Study the graph and answer the questions.
 The average marks of Hindi and English is

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According to given bar graph , we have
Sum of marks of Hindi and English = 70 + 40
Number of subjects = 2Required average = Sum of marks of Hindi and English Number of subjects
Correct Option: C
According to given bar graph , we have
Sum of marks of Hindi and English = 70 + 40
Number of subjects = 2Required average = Sum of marks of Hindi and English Number of subjects Required average = 70 + 40 = 110 = 55 2 2
 The ratio of the marks of Maths and History is

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On the basis of given graph in question ,
The marks of Maths = 80
and the marks of History = 60
Required ratio = The marks of Maths : The marks of HistoryCorrect Option: D
On the basis of given graph in question ,
The marks of Maths = 80
and the marks of History = 60
Required ratio = The marks of Maths : The marks of History
∴ Required ratio = 80 : 60 = 4 : 3
Direction: The bar diagram below shows the production of potatoes (in quintals) from the year 2000 to 2006. Study the diagram and answer the following questions.
 During this period, the highest rate of decline in production is:

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According to given bar graph , we have
The production of potatoes in 2004 = 1240
The production of potatoes in 2003 = 1640
Change in production = The production of potatoes in 2003  The production of potatoes in 2004 = 1640  1240 = 400Percent rate of decline in year 2004 = Change in production × 100 The production of potatoes in 2003 Percent rate of decline in year 2004 = 400 × 100 1640
The production of potatoes in 2002 = 720
The production of potatoes in 2001 = 1085
Change in production = The production of potatoes in 2001  The production of potatoes in 2002 = 1085  720 = 365Percent rate of decline in year 2002 = Change in production × 100 The production of potatoes in 2001
Correct Option: C
According to given bar graph , we have
The production of potatoes in 2004 = 1240
The production of potatoes in 2003 = 1640
Change in production = The production of potatoes in 2003  The production of potatoes in 2004 = 1640  1240 = 400Percent rate of decline in year 2004 = Change in production × 100 The production of potatoes in 2003 Percent rate of decline in year 2004 = 400 × 100 1640
The production of potatoes in 2002 = 720
The production of potatoes in 2001 = 1085
Change in production = The production of potatoes in 2001  The production of potatoes in 2002 = 1085  720 = 365Percent rate of decline in year 2002 = Change in production × 100 The production of potatoes in 2001 Percent rate of decline in year 2002 = 365 × 100 = 33.64% 1085