Introduction to Data Interpretation
Direction: Sales of books (in thousands} from six branches (B1, B2, B3, B4, B5, B6) of a publishing company are given below. Study the graph and answer the following questions.
- If the sale of books from the branch B2 increases by 30% and that from the branch B4 decreases by 10%, the approximate sale from all the six branches will
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On the basis of given graph in question ,
The sale of books from the branch B2 = 40
After increases by 30% ,New sale of books from branch B2 = 40 × 130 = 52 thousand 100
The sale of books from the branch B2 = 80
After decreases by 10% , thenNew sale of books from branch B4 = 80 × 90 = 72 thousand 100 New average sales = 304 6 New average sales = 152 thousand 3 Increase = 152 - 50 = 2 thousand 3 3
Correct Option: A
On the basis of given graph in question ,
The sale of books from the branch B2 = 40
After increases by 30% ,New sale of books from branch B2 = 40 × 130 = 52 thousand 100
The sale of books from the branch B2 = 80
After decreases by 10% , thenNew sale of books from branch B4 = 80 × 90 = 72 thousand 100 New average sales = 304 6 New average sales = 152 thousand 3 Increase = 152 - 50 = 2 thousand 3 3 ∴ Percentage increase = 2 × 100 = 4 = 1.33% 3 × 50 3
- The number of branches in which sales of books are below the average level is
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As per the given bar graph in question ,
Sum of sales of all branches = 20 + 40 + 55 + 80 + 55 + 60 = 300 thousands
Total number of branches = 6Average sales of all branches = Sum of sales of all branches = thousand Total number of branches
Correct Option: B
As per the given bar graph in question ,
Sum of sales of all branches = 20 + 40 + 55 + 80 + 55 + 60 = 300 thousands
Total number of branches = 6Average sales of all branches = Sum of sales of all branches = thousand Total number of branches Average sales of all branches = 300 = thousand 6
The sale of branches B1, B2 and B5 are less than the average sales.
- The average sales of the branches B1 and B4 is equal to the average sales of the branches
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On the basis of given graph in question ,
Sum of sales of the branches B1 and B4 = 20 + 80 = 100
Number of branches = 2Average sales of the branches B1 and B4 = 100 = 50thousand 2
And Sum of sales of the branches B3 and B5 = 55 + 45 = 100
Number of branches = 2
Correct Option: A
On the basis of given graph in question ,
Sum of sales of the branches B1 and B4 = 20 + 80 = 100
Number of branches = 2Average sales of the branches B1 and B4 = 100 = 50thousand 2
And Sum of sales of the branches B3 and B5 = 55 + 45 = 100
Number of branches = 2Average sales of the branches B3 and B5 = 100 = 50thousand 2
Direction: The following bar graph shows the production of fertilizers (in lakh tonnes) by a company, in six consecutive years. Study the graph and answer the questions.
- Percentage increase in production of fertilizers for a year with respect to its previous year was maximum in the year
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As per the given bar graph in question , we see that percentage increase in production of fertilizers for a year with respect to 1999 year is maximum in the year 2000 .
Correct Option: D
As per the given bar graph in question , we see that percentage increase in production of fertilizers for a year with respect to 1999 is maximum in the year 2000 . So , required answer is option D.
- The year in which the production of fertilizers is nearest to the average production of all the six years, is
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According to given bar graph in question ,
Sum of the production of fertilizers all six years = 70 + 80 + 90 + 80 + 60 + 75 = 455 lakh tonnes
Total number of years = 6In year 2000 average production of fertilizers = 455 = 75 5 lakh tonnes 6 6 Correct Option: D
According to given bar graph in question ,
Sum of the production of fertilizers all six years = 70 + 80 + 90 + 80 + 60 + 75 = 455 lakh tonnes
Total number of years = 6In year 2000 average production of fertilizers = 455 = 75 5 lakh tonnes 6 6
Hence , required answer is 2000 year .
