Introduction to Data Interpretation
Direction: Sales of books (in thousands} from six branches (B1, B2, B3, B4, B5, B6) of a publishing company are given below. Study the graph and answer the following questions.
 If the sale of books from the branch B2 increases by 30% and that from the branch B4 decreases by 10%, the approximate sale from all the six branches will

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On the basis of given graph in question ,
The sale of books from the branch B2 = 40
After increases by 30% ,New sale of books from branch B2 = 40 × 130 = 52 thousand 100
The sale of books from the branch B2 = 80
After decreases by 10% , thenNew sale of books from branch B4 = 80 × 90 = 72 thousand 100 New average sales = 304 6 New average sales = 152 thousand 3 Increase = 152  50 = 2 thousand 3 3
Correct Option: A
On the basis of given graph in question ,
The sale of books from the branch B2 = 40
After increases by 30% ,New sale of books from branch B2 = 40 × 130 = 52 thousand 100
The sale of books from the branch B2 = 80
After decreases by 10% , thenNew sale of books from branch B4 = 80 × 90 = 72 thousand 100 New average sales = 304 6 New average sales = 152 thousand 3 Increase = 152  50 = 2 thousand 3 3 ∴ Percentage increase = 2 × 100 = 4 = 1.33% 3 × 50 3
 The number of branches in which sales of books are below the average level is

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As per the given bar graph in question ,
Sum of sales of all branches = 20 + 40 + 55 + 80 + 55 + 60 = 300 thousands
Total number of branches = 6Average sales of all branches = Sum of sales of all branches = thousand Total number of branches
Correct Option: B
As per the given bar graph in question ,
Sum of sales of all branches = 20 + 40 + 55 + 80 + 55 + 60 = 300 thousands
Total number of branches = 6Average sales of all branches = Sum of sales of all branches = thousand Total number of branches Average sales of all branches = 300 = thousand 6
The sale of branches B1, B2 and B5 are less than the average sales.
 The average sales of the branches B1 and B4 is equal to the average sales of the branches

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On the basis of given graph in question ,
Sum of sales of the branches B1 and B4 = 20 + 80 = 100
Number of branches = 2Average sales of the branches B1 and B4 = 100 = 50thousand 2
And Sum of sales of the branches B3 and B5 = 55 + 45 = 100
Number of branches = 2
Correct Option: A
On the basis of given graph in question ,
Sum of sales of the branches B1 and B4 = 20 + 80 = 100
Number of branches = 2Average sales of the branches B1 and B4 = 100 = 50thousand 2
And Sum of sales of the branches B3 and B5 = 55 + 45 = 100
Number of branches = 2Average sales of the branches B3 and B5 = 100 = 50thousand 2
Direction: The following bar graph shows the production of fertilizers (in lakh tonnes) by a company, in six consecutive years. Study the graph and answer the questions.
 Percentage increase in production of fertilizers for a year with respect to its previous year was maximum in the year

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As per the given bar graph in question , we see that percentage increase in production of fertilizers for a year with respect to 1999 year is maximum in the year 2000 .
Correct Option: D
As per the given bar graph in question , we see that percentage increase in production of fertilizers for a year with respect to 1999 is maximum in the year 2000 . So , required answer is option D.
 The year in which the production of fertilizers is nearest to the average production of all the six years, is

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According to given bar graph in question ,
Sum of the production of fertilizers all six years = 70 + 80 + 90 + 80 + 60 + 75 = 455 lakh tonnes
Total number of years = 6In year 2000 average production of fertilizers = 455 = 75 5 lakh tonnes 6 6 Correct Option: D
According to given bar graph in question ,
Sum of the production of fertilizers all six years = 70 + 80 + 90 + 80 + 60 + 75 = 455 lakh tonnes
Total number of years = 6In year 2000 average production of fertilizers = 455 = 75 5 lakh tonnes 6 6
Hence , required answer is 2000 year .