Introduction to Data Interpretation
Direction: Study the graph and answer the questions.
- In case of which soft drink was the average annual sale maximum during the period 1988-1993?
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As per the given bar graph , we have
Total annual sales of cool-sip = 25 + 6 + 19 + 15 + 25 + 30 = 120
Number of given years = 6Average annual sales of cool-sip during 1988 – 1993 = 
Total annual sales of cool-sip 
Number of given years Average annual sales of cool-sip during 1988 – 1993 = 120 = 20 lakh bottles 6
Total annual sales of Pep -up = 30 + 35 + 30 + 25 + 20 + 20 = 160
Number of given years = 6Average annual sales of Pep -up during 1988 – 1993 = Total annual sales of Pep -up Number of given years
Correct Option: A
As per the given bar graph , we have
Total annual sales of cool-sip = 25 + 6 + 19 + 15 + 25 + 30 = 120
Number of given years = 6Average annual sales of cool-sip during 1988 – 1993 = Total annual sales of cool-sip Number of given years Average annual sales of cool-sip during 1988 – 1993 = 120 = 20 lakh bottles 6
Total annual sales of Pep -up = 30 + 35 + 30 + 25 + 20 + 20 = 160
Number of given years = 6Average annual sales of Pep -up during 1988 – 1993 = Total annual sales of Pep -up Number of given years Average annual sales of Pep -up during 1988 – 1993 = 160 = 26 2 lakh bottles. 6 3
- In which year the sale of cool-sip is minimum?
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From the given bar diagram , we see
Minimum sales in 1989 = 60 lakh bottlesCorrect Option: D
From the given bar diagram , we see
Minimum sales in 1989 = 60 lakh bottles
Hence , the sale of cool-sip is minimum in 1989 year .
Direction: The graph shows the result of 10th class students of a school for 4 years. Study the graph and answer the questions :
- The ratio of students who scored second class to the total students appeared in the year 2000 is
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According to given bar graph , we have
Number of students who scored second class in the year 2000 = 50
Total students appeared in the year 2000 = 20 + 50 + 90 = 160
Required ratio = Number of students who scored second class in the year 2000 : Total students appeared in the year 2000Correct Option: C
According to given bar graph , we have
Number of students who scored second class in the year 2000 = 50
Total students appeared in the year 2000 = 20 + 50 + 90 = 160
Required ratio = Number of students who scored second class in the year 2000 : Total students appeared in the year 2000
Required ratio = 50 : 160 = 5 : 16
- The year in which the maximum number of students appeared for the 10th class exam is
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As per the given bar graph , we have
Number of students in Year 2000 ⇒ 20 + 50 + 90
= 160
Number of students in Year 2001 ⇒ 30 + 60 + 110 = 200
Number of students in Year 2002 ⇒ 15 + 60 + 120 = 195Correct Option: A
As per the given bar graph , we have
Number of students in Year 2000 ⇒ 20 + 50 + 90
= 160
Number of students in Year 2001 ⇒ 30 + 60 + 110 = 200
Number of students in Year 2002 ⇒ 15 + 60 + 120 = 195
Number of students in Year 2003 ⇒ 10 + 40 + 120 = 170
Hence , required answer is 2001 year .
- The percentage increase of first-class in the year 2003 over the year 2002 is approximately
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From the given bar diagram , we see
Number of students of first-class in the year 2003 = 120
Number of students of first-class in the year 2002 = 120
Increase = 120 - 120 = 0Required % increase = Increase × 100 Number of students of first-class in the year 2002
Correct Option: B
From the given bar diagram , we see
Number of students of first-class in the year 2003 = 120
Number of students of first-class in the year 2002 = 120
Increase = 120 - 120 = 0Required % increase = Increase × 100 Number of students of first-class in the year 2002 Required % increase = 0 × 100 = 0 120
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