## Introduction to Data Interpretation

#### Data Interpretation

Direction: Study the graph and answer the questions. 1. In case of which soft drink was the average annual sale maximum during the period 1988-1993?

1. As per the given bar graph , we have
Total annual sales of cool-sip = 25 + 6 + 19 + 15 + 25 + 30 = 120
Number of given years = 6

 Average annual sales of cool-sip during 1988 – 1993 = Total annual sales of cool-sip Number of given years
 Average annual sales of cool-sip during 1988 – 1993 = 120 = 20 lakh bottles 6

Total annual sales of Pep -up = 30 + 35 + 30 + 25 + 20 + 20 = 160
Number of given years = 6

##### Correct Option: A

As per the given bar graph , we have
Total annual sales of cool-sip = 25 + 6 + 19 + 15 + 25 + 30 = 120
Number of given years = 6

 Average annual sales of Pep -up during 1988 – 1993 = Total annual sales of Pep -up Number of given years

 Average annual sales of cool-sip during 1988 – 1993 = Total annual sales of cool-sip Number of given years
 Average annual sales of cool-sip during 1988 – 1993 = 120 = 20 lakh bottles 6

Total annual sales of Pep -up = 30 + 35 + 30 + 25 + 20 + 20 = 160
Number of given years = 6

 Average annual sales of Pep -up during 1988 – 1993 = Total annual sales of Pep -up Number of given years
 Average annual sales of Pep -up during 1988 – 1993 = 160 = 26 2 lakh bottles. 6 3

1. In which year the sale of cool-sip is minimum?

1. From the given bar diagram , we see
Minimum sales in 1989 = 60 lakh bottles

##### Correct Option: D

From the given bar diagram , we see
Minimum sales in 1989 = 60 lakh bottles
Hence , the sale of cool-sip is minimum in 1989 year .

Direction: The graph shows the result of 10th class students of a school for 4 years. Study the graph and answer the questions : 1. The ratio of students who scored second class to the total students appeared in the year 2000 is

1. According to given bar graph , we have
Number of students who scored second class in the year 2000 = 50
Total students appeared in the year 2000 = 20 + 50 + 90 = 160
Required ratio = Number of students who scored second class in the year 2000 : Total students appeared in the year 2000

##### Correct Option: C

According to given bar graph , we have
Number of students who scored second class in the year 2000 = 50
Total students appeared in the year 2000 = 20 + 50 + 90 = 160
Required ratio = Number of students who scored second class in the year 2000 : Total students appeared in the year 2000
Required ratio = 50 : 160 = 5 : 16

1. The year in which the maximum number of students appeared for the 10th class exam is

1. As per the given bar graph , we have
Number of students in Year 2000 ⇒ 20 + 50 + 90
= 160
Number of students in Year 2001 ⇒ 30 + 60 + 110 = 200
Number of students in Year 2002 ⇒ 15 + 60 + 120 = 195

##### Correct Option: A

As per the given bar graph , we have
Number of students in Year 2000 ⇒ 20 + 50 + 90
= 160
Number of students in Year 2001 ⇒ 30 + 60 + 110 = 200
Number of students in Year 2002 ⇒ 15 + 60 + 120 = 195
Number of students in Year 2003 ⇒ 10 + 40 + 120 = 170
Hence , required answer is 2001 year .

1. The percentage increase of first-class in the year 2003 over the year 2002 is approximately

1. From the given bar diagram , we see
Number of students of first-class in the year 2003 = 120
Number of students of first-class in the year 2002 = 120
Increase = 120 - 120 = 0

 Required % increase = Increase × 100 Number of students of first-class in the year 2002

##### Correct Option: B

From the given bar diagram , we see
Number of students of first-class in the year 2003 = 120
Number of students of first-class in the year 2002 = 120
Increase = 120 - 120 = 0

 Required % increase = Increase × 100 Number of students of first-class in the year 2002

 Required % increase = 0 × 100 = 0 120