Introduction to Data Interpretation


Direction: Study the graph and answer the questions.

  1. In case of which soft drink was the average annual sale maximum during the period 1988-1993?









  1. View Hint View Answer Discuss in Forum

    As per the given bar graph , we have
    Total annual sales of cool-sip = 25 + 6 + 19 + 15 + 25 + 30 = 120
    Number of given years = 6


    Average annual sales of cool-sip during 1988 – 1993 = Total annual sales of cool-sip
    Number of given years
    Average annual sales of cool-sip during 1988 – 1993 =
    120
    = 20 lakh bottles
    6

    Total annual sales of Pep -up = 30 + 35 + 30 + 25 + 20 + 20 = 160
    Number of given years = 6

    Correct Option: A

    As per the given bar graph , we have
    Total annual sales of cool-sip = 25 + 6 + 19 + 15 + 25 + 30 = 120
    Number of given years = 6

    Average annual sales of Pep -up during 1988 – 1993 = Total annual sales of Pep -up
    Number of given years

    Average annual sales of cool-sip during 1988 – 1993 = Total annual sales of cool-sip
    Number of given years
    Average annual sales of cool-sip during 1988 – 1993 =
    120
    = 20 lakh bottles
    6

    Total annual sales of Pep -up = 30 + 35 + 30 + 25 + 20 + 20 = 160
    Number of given years = 6

    Average annual sales of Pep -up during 1988 – 1993 = Total annual sales of Pep -up
    Number of given years
    Average annual sales of Pep -up during 1988 – 1993 =
    160
    = 26
    2
    lakh bottles.
    63


  1. In which year the sale of cool-sip is minimum?









  1. View Hint View Answer Discuss in Forum

    From the given bar diagram , we see
    Minimum sales in 1989 = 60 lakh bottles

    Correct Option: D

    From the given bar diagram , we see
    Minimum sales in 1989 = 60 lakh bottles
    Hence , the sale of cool-sip is minimum in 1989 year .


Direction: The graph shows the result of 10th class students of a school for 4 years. Study the graph and answer the questions :

  1. The ratio of students who scored second class to the total students appeared in the year 2000 is









  1. View Hint View Answer Discuss in Forum

    According to given bar graph , we have
    Number of students who scored second class in the year 2000 = 50
    Total students appeared in the year 2000 = 20 + 50 + 90 = 160
    Required ratio = Number of students who scored second class in the year 2000 : Total students appeared in the year 2000

    Correct Option: C

    According to given bar graph , we have
    Number of students who scored second class in the year 2000 = 50
    Total students appeared in the year 2000 = 20 + 50 + 90 = 160
    Required ratio = Number of students who scored second class in the year 2000 : Total students appeared in the year 2000
    Required ratio = 50 : 160 = 5 : 16


  1. The year in which the maximum number of students appeared for the 10th class exam is









  1. View Hint View Answer Discuss in Forum

    As per the given bar graph , we have
    Number of students in Year 2000 ⇒ 20 + 50 + 90
    = 160
    Number of students in Year 2001 ⇒ 30 + 60 + 110 = 200
    Number of students in Year 2002 ⇒ 15 + 60 + 120 = 195

    Correct Option: A

    As per the given bar graph , we have
    Number of students in Year 2000 ⇒ 20 + 50 + 90
    = 160
    Number of students in Year 2001 ⇒ 30 + 60 + 110 = 200
    Number of students in Year 2002 ⇒ 15 + 60 + 120 = 195
    Number of students in Year 2003 ⇒ 10 + 40 + 120 = 170
    Hence , required answer is 2001 year .


  1. The percentage increase of first-class in the year 2003 over the year 2002 is approximately









  1. View Hint View Answer Discuss in Forum

    From the given bar diagram , we see
    Number of students of first-class in the year 2003 = 120
    Number of students of first-class in the year 2002 = 120
    Increase = 120 - 120 = 0

    Required % increase =
    Increase
    × 100
    Number of students of first-class in the year 2002

    Correct Option: B

    From the given bar diagram , we see
    Number of students of first-class in the year 2003 = 120
    Number of students of first-class in the year 2002 = 120
    Increase = 120 - 120 = 0

    Required % increase =
    Increase
    × 100
    Number of students of first-class in the year 2002

    Required % increase =
    0
    × 100 = 0
    120