Introduction to Data Interpretation

Introduction to Data Interpretation

Easy Questions
Moderate Questions
Difficult Questions

Data Interpretation

Introduction to Data Interpretation
Table chart
Line chart
Pie chart
Bar graph
Mixed Graph
Data Sufficiency

Direction: The bar graph given here shows the number of job- seekers of a state in various years at different stages of education. Study the graph carefully and answer the questions based on it.

  1. In which year, was the number of Matriculate job-seekers maximum?








  1. View Hint View Answer Discuss in Forum

    On the basis of given graph in question ,
    Year 1976 , Total number of job seekers = 3300
    Number of Graduate and senior secondary job- seekers = 1800
    ∴ Number of Matriculate job- seekers = 3300 – 1800 = 1500
    Year 1977 , Total number of job seekers = 4000
    Number of Graduate and senior secondary job- seekers = 2200
    ∴ Number of Matriculate job- seekers =
    4000 – 2200 = 1800 ⇒ maximum

    Correct Option: D

    On the basis of given graph in question ,
    Year 1976 , Total number of job seekers = 3300
    Number of Graduate and senior secondary job- seekers = 1800
    ∴ Number of Matriculate job- seekers = 3300 – 1800 = 1500
    Year 1977 , Total number of job seekers = 4000
    Number of Graduate and senior secondary job- seekers = 2200
    ∴ Number of Matriculate job- seekers =
    4000 – 2200 = 1800 ⇒ maximum
    Hence , required answer is 1977 year .

  1. In comparison to the year 1973, how many more job-seekers in all, were there in the year 1977?








  1. View Hint View Answer Discuss in Forum

    According to given bar graph , we have
    → Year 1973 , Number of job-seekers = 1625
    → Year 1977 , Number of job-seekers = 4000
    Required difference = Number of job-seekers in 1977 - Number of job-seekers in 1973

    Correct Option: C

    According to given bar graph , we have
    → Year 1973 , Number of job-seekers = 1625
    → Year 1977 , Number of job-seekers = 4000
    Required difference = Number of job-seekers in 1977 - Number of job-seekers in 1973
    ∴ Required difference = 4000 – 1625 = 2375

  1. In which year was the number of Graduate job-seekers the same as that of Senior Secondary job- seekers?








  1. View Hint View Answer Discuss in Forum

    On the basis of given graph in question ,
    Number of Graduate job- seekers in 1974 = 525
    Total number of Graduate and Senior secondary job- seekers in 1974 = 1050

    Correct Option: B

    On the basis of given graph in question ,
    Number of Graduate job- seekers in 1974 = 525
    Total number of Graduate and Senior secondary job- seekers in 1974 = 1050
    ∴ Number of Senior secondary job -seekers in 1974 = 1050 – 525 = 525

Direction: The following is a horizontal bar diagram showing the accidents in which two-wheelers are involved with other objects. Study the diagram and answer the questions.

  1. The percentage by which the accidents involving buses is less than the accidents involving tanker lorry is








  1. View Hint View Answer Discuss in Forum

    From the given bar diagram , we see that one box represents a number of 20 units.
    Number of the accidents involving buses = 6 boxes = 6 × 20 = 120 units
    Number of the accidents involving tanker lorry = 8 boxes = 8 × 20 = 160 units
    Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 units

    Correct Option: B

    From the given bar diagram , we see that one box represents a number of 20 units.
    Number of the accidents involving buses = 6 boxes = 6 × 20 = 120 units
    Number of the accidents involving tanker lorry = 8 boxes = 8 × 20 = 160 units
    Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 units

    Required difference =
    160 - 120
    		 × 100 = 4%
    1000

  1. The percentage of accidents in which pedestrians and cyclists are involved is








  1. View Hint View Answer Discuss in Forum

    As per the given bar diagram , we see that one box represents a number of 20 units.
    Number of the accidents involving pedestrians = 2 boxes = 2 × 20 = 40 units
    Number of the accidents involving cyclists = 10 boxes = 10 × 20 = 200 units
    Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 units

    Required percentage =
    40 + 200
    		× 100
    1000

    Correct Option: A

    As per the given bar diagram , we see that one box represents a number of 20 units.
    Number of the accidents involving pedestrians = 2 boxes = 2 × 20 = 40 units
    Number of the accidents involving cyclists = 10 boxes = 10 × 20 = 200 units
    Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000 units

    Required percentage =
    40 + 200
    		× 100
    1000

    Required percentage =
    24000
    		= 24%
    1000