Introduction to Data Interpretation
Direction: Given here is a multiple bar diagram of the scores of four players in two innings. Study the diagram and answer the questions.
 The average runs of two innings of the player who scored highest in average are :

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According to given bar graph , we have
Total number of runs of two innings who scored highest = 60 + 80 = 140
Number of innings = 2Required average runs = Total number of runs of two innings who scored highest = 140 Number of innings 2
Correct Option: A
According to given bar graph , we have
Total number of runs of two innings who scored highest = 60 + 80 = 140
Number of innings = 2Required average runs = Total number of runs of two innings who scored highest = 140 Number of innings 2
Required average runs = 70
The required cricketer is Mahendra Singh Dhoni.
Direction: Study the following bar diagram carefully and answer the following questions.
 The ratio of production of TVs in the years 2009 and 2010 is

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On the basis of given graph in question ,
Number of production of TVs in the year 2009 = 6000
Number of production of TVs in the year 2010 = 9000
Required ratio = Number of production of TVs in the year 2009 : Number of production of TVs in the year 2010Correct Option: C
On the basis of given graph in question ,
Number of production of TVs in the year 2009 = 6000
Number of production of TVs in the year 2010 = 9000
Required ratio = Number of production of TVs in the year 2009 : Number of production of TVs in the year 2010
Hence , Required ratio = 6000 : 9000 = 2 : 3
 The difference between averages of production of TVs and LCDs from 2009 to 2012 is

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From the given bar diagram , we see
Total production of T.V. from 2009 to 2012 = 6000 + 9000 + 13000 + 11000 = 39000
Number of given years = 4Average production of T.V. from 2009 to 2012 = Total production of T.V. from 2009 to 2012 Number of given years Average production of T.V. from 2009 to 2012 = 39000 = 9750 4
Total production of L.C.D from 2009 to 2012 = 7000 + 9400 + 9000 + 10000 = 35400
Number of given years = 4Average production of LCD from 2009 to 2012 = Total production of L.C.D from 2009 to 2012 Number of given years
Correct Option: D
From the given bar diagram , we see
Total production of T.V. from 2009 to 2012 = 6000 + 9000 + 13000 + 11000 = 39000
Number of given years = 4Average production of T.V. from 2009 to 2012 = Total production of T.V. from 2009 to 2012 Number of given years Average production of T.V. from 2009 to 2012 = 39000 = 9750 4
Total production of L.C.D from 2009 to 2012 = 7000 + 9400 + 9000 + 10000 = 35400
Number of given years = 4Average production of LCD from 2009 to 2012 = Total production of L.C.D from 2009 to 2012 Number of given years Average production of LCD from 2009 to 2012 = 35400 = 8850 4
Required difference = Average production of TV from 2009 to 2012  Average production of LCD from 2009 to 2012
∴ Required difference = 9750 – 8850 = 900
 The ratio of production of LCDs in the year 2011 and 2013 is

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On the basis of given graph in question ,
Number of production of LCDs in the year 2011 = 9000
Number of production of LCDs in the year 2013 = 12000
Required Ratio = Number of production of LCDs in the year 2011 : Number of production of LCDs in the year 2013Correct Option: A
On the basis of given graph in question ,
Number of production of LCDs in the year 2011 = 9000
Number of production of LCDs in the year 2013 = 12000
Required Ratio = Number of production of LCDs in the year 2011 : Number of production of LCDs in the year 2013
∴ Required Ratio = 9000 : 12000 = 3 : 4
 The total number of products of electronic items is maximum in the year

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According to given bar graph , we have
Total production of electronic items in year 2009 ⇒ 6000 + 7000 = 13000
Total production of electronic items in year 2010 ⇒ 9000 + 9400 = 18400
Total production of electronic items in year 2011 ⇒ 13000 + 9000 = 22000
Total production of electronic items in year 2012 ⇒ 11000 + 10000 = 21000
Total production of electronic items in year 2013 ⇒ 8000 + 12000 = 20000Correct Option: C
According to given bar graph , we have
Total production of electronic items in year 2009 ⇒ 6000 + 7000 = 13000
Total production of electronic items in year 2010 ⇒ 9000 + 9400 = 18400
Total production of electronic items in year 2011 ⇒ 13000 + 9000 = 22000
Total production of electronic items in year 2012 ⇒ 11000 + 10000 = 21000
Total production of electronic items in year 2013 ⇒ 8000 + 12000 = 20000
Hence , The total number of products of electronic items is maximum in the year 2011 .