Introduction to Data Interpretation
Direction: Given here is a multiple bar diagram of the scores of four players in two innings. Study the diagram and answer the questions.

- The average runs of two innings of the player who scored highest in average are :
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According to given bar graph , we have
Total number of runs of two innings who scored highest = 60 + 80 = 140
Number of innings = 2Required average runs = Total number of runs of two innings who scored highest = 140 Number of innings 2
Correct Option: A
According to given bar graph , we have
Total number of runs of two innings who scored highest = 60 + 80 = 140
Number of innings = 2Required average runs = Total number of runs of two innings who scored highest = 140 Number of innings 2
Required average runs = 70
The required cricketer is Mahendra Singh Dhoni.
Direction: Study the following bar diagram carefully and answer the following questions.

- The ratio of production of TVs in the years 2009 and 2010 is
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On the basis of given graph in question ,
Number of production of TVs in the year 2009 = 6000
Number of production of TVs in the year 2010 = 9000
Required ratio = Number of production of TVs in the year 2009 : Number of production of TVs in the year 2010Correct Option: C
On the basis of given graph in question ,
Number of production of TVs in the year 2009 = 6000
Number of production of TVs in the year 2010 = 9000
Required ratio = Number of production of TVs in the year 2009 : Number of production of TVs in the year 2010
Hence , Required ratio = 6000 : 9000 = 2 : 3
- The difference between averages of production of TVs and LCDs from 2009 to 2012 is
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From the given bar diagram , we see
Total production of T.V. from 2009 to 2012 = 6000 + 9000 + 13000 + 11000 = 39000
Number of given years = 4Average production of T.V. from 2009 to 2012 = Total production of T.V. from 2009 to 2012 Number of given years Average production of T.V. from 2009 to 2012 = 39000 = 9750 4
Total production of L.C.D from 2009 to 2012 = 7000 + 9400 + 9000 + 10000 = 35400
Number of given years = 4Average production of LCD from 2009 to 2012 = Total production of L.C.D from 2009 to 2012 Number of given years
Correct Option: D
From the given bar diagram , we see
Total production of T.V. from 2009 to 2012 = 6000 + 9000 + 13000 + 11000 = 39000
Number of given years = 4Average production of T.V. from 2009 to 2012 = Total production of T.V. from 2009 to 2012 Number of given years Average production of T.V. from 2009 to 2012 = 39000 = 9750 4
Total production of L.C.D from 2009 to 2012 = 7000 + 9400 + 9000 + 10000 = 35400
Number of given years = 4Average production of LCD from 2009 to 2012 = Total production of L.C.D from 2009 to 2012 Number of given years Average production of LCD from 2009 to 2012 = 35400 = 8850 4
Required difference = Average production of TV from 2009 to 2012 - Average production of LCD from 2009 to 2012
∴ Required difference = 9750 – 8850 = 900
- The ratio of production of LCDs in the year 2011 and 2013 is
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On the basis of given graph in question ,
Number of production of LCDs in the year 2011 = 9000
Number of production of LCDs in the year 2013 = 12000
Required Ratio = Number of production of LCDs in the year 2011 : Number of production of LCDs in the year 2013Correct Option: A
On the basis of given graph in question ,
Number of production of LCDs in the year 2011 = 9000
Number of production of LCDs in the year 2013 = 12000
Required Ratio = Number of production of LCDs in the year 2011 : Number of production of LCDs in the year 2013
∴ Required Ratio = 9000 : 12000 = 3 : 4
- The total number of products of electronic items is maximum in the year
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According to given bar graph , we have
Total production of electronic items in year 2009 ⇒ 6000 + 7000 = 13000
Total production of electronic items in year 2010 ⇒ 9000 + 9400 = 18400
Total production of electronic items in year 2011 ⇒ 13000 + 9000 = 22000
Total production of electronic items in year 2012 ⇒ 11000 + 10000 = 21000
Total production of electronic items in year 2013 ⇒ 8000 + 12000 = 20000Correct Option: C
According to given bar graph , we have
Total production of electronic items in year 2009 ⇒ 6000 + 7000 = 13000
Total production of electronic items in year 2010 ⇒ 9000 + 9400 = 18400
Total production of electronic items in year 2011 ⇒ 13000 + 9000 = 22000
Total production of electronic items in year 2012 ⇒ 11000 + 10000 = 21000
Total production of electronic items in year 2013 ⇒ 8000 + 12000 = 20000
Hence , The total number of products of electronic items is maximum in the year 2011 .