## Introduction to Data Interpretation

#### Data Interpretation

Direction: The following is a horizontal bar diagram showing the accidents in which two-wheelers are involved with other objects. Study the diagram and answer the questions. 1. The percentage by which the accidents involving buses is less than the accidents involving tanker lorry is

1. As per the given above bar diagram , we see that one box represents the number of 20.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Number of accidents involving buses = 120
Number of accidents involving tanker lorry = 160
Difference = 160 - 120 = 40

##### Correct Option: B

As per the given above bar diagram , we see that one box represents the number of 20.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Number of accidents involving buses = 120
Number of accidents involving tanker lorry = 160
Difference = 160 - 120 = 40

 Required percentage = 40 × 100 = 4% 1000

1. The percentage of accidents in which pedestrians and cyclists are involved is

1. According to given bar diagram , we have
Number of accidents involving pedestrians and cyclists = 40 + 200 = 240
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000

 Required percentage = Number of accidents involving pedestrians and cyclists × 100 Total accidents

##### Correct Option: A

According to given bar diagram , we have
Number of accidents involving pedestrians and cyclists = 40 + 200 = 240
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000

 Required percentage = Number of accidents involving pedestrians and cyclists × 100 Total accidents

 Required percentage = 240 × 100 = 24% 1000

1. If the data of the bar diagram is represented by a pie-chart, and the angle of a sector of the pie- chart is 36°, then this sector represents the accidents involving

1. On the basis of given the bar diagram is represented by a pie-chart in question ,
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Total corresponding angle of pie chart = 360°
∵ 1000 ≈ 360 °

##### Correct Option: D

On the basis of given the bar diagram is represented by a pie-chart in question ,
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Total corresponding angle of pie chart = 360°
∵ 1000 ≈ 360 °

 ∴ 100 ≡ 360 × 100 = 36 ° 1000

Therefore , required answer is stationary vehicles .

1. 60% of the accidents are involved due to

1. As per the given above bar diagram , we see that one box represents the number of 20.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Two-wheelers + Cars + Buses + Stationary Vehicles = 230 + 150 + 120 + 100 = 600

##### Correct Option: C

As per the given above bar diagram , we see that one box represents the number of 20.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Two-wheelers + Cars + Buses + Stationary Vehicles = 230 + 150 + 120 + 100 = 600

 Required percent = 600 × 100 = 60% 1000

Hence , required answer is option C.

1. The difference in percentage between the accidents involving two-wheelers and two-wheelers and two-wheelers and other objects is respectively.

1. On the basis of given bar diagram in question ,we see that one box represents the number of 20.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Number of accidents involving two-wheelers and two-wheelers = 230
Number of accidents involving two-wheelers and other objects = 770

 Percentage of accidents involving two-wheelers and two wheelers = 230 × 100 = 23% 1000

##### Correct Option: D

On the basis of given bar diagram in question ,we see that one box represents the number of 20.
Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Number of accidents involving two-wheelers and two-wheelers = 230
Number of accidents involving two-wheelers and other objects = 770

 Percentage of accidents involving two-wheelers and two wheelers = 230 × 100 = 23% 1000

 Percentage of accidents involving two-wheelers and other objects = 770 × 100 = 77% 1000

∴ Required difference = Percentage of accidents involving two-wheelers and other objects - Percentage of accidents involving two-wheelers and two wheelers
Required difference = 77 – 23 = 54%