Introduction to Data Interpretation

Introduction to Data Interpretation

Easy Questions
Moderate Questions
Difficult Questions

Data Interpretation

Introduction to Data Interpretation
Table chart
Line chart
Pie chart
Bar graph
Mixed Graph
Data Sufficiency

Direction: The following bar graph shows the production of fertilizers (in lakh tonnes) by a company, in six consecutive years. Study the graph and answer the questions.

  1. The year in which the production of fertilizers is nearest to the average production of all the six years, is








  1. View Hint View Answer Discuss in Forum

    According to given bar graph in question ,
    Sum of the production of fertilizers all six years = 70 + 80 + 90 + 80 + 60 + 75 = 455 lakh tonnes
    Total number of years = 6

    In year 2000 average production of fertilizers =
    455
    		= 75
    5
    		 lakh tonnes
    66

    Correct Option: D

    According to given bar graph in question ,
    Sum of the production of fertilizers all six years = 70 + 80 + 90 + 80 + 60 + 75 = 455 lakh tonnes
    Total number of years = 6

    In year 2000 average production of fertilizers =
    455
    		= 75
    5
    		 lakh tonnes
    66

    Hence , required answer is 2000 year .

  1. The total production of fertilizers in the year 1998 and 2000 is X% of the total production in the years 1997 and 1999. Then X is equal to








  1. View Hint View Answer Discuss in Forum

    On the basis of given graph in question , we have
    The total production of fertilizers in the year 1998 and 2000 = ( 90 + 60 ) = 150
    The total production in the years 1997 and 1999 = ( 80 + 75 ) = 155

    The total production of fertilizers in the year 1998 and 2000 ×
    X
    		 = The total production in the years 1997 and 1999
    100

    ⇒
    150 × X
    		= 155
    100

    ⇒ X =
    155 × 100
    		 =
    310
    1503

    Correct Option: A

    On the basis of given graph in question , we have
    The total production of fertilizers in the year 1998 and 2000 = ( 90 + 60 ) = 150
    The total production in the years 1997 and 1999 = ( 80 + 75 ) = 155

    The total production of fertilizers in the year 1998 and 2000 ×
    X
    		 = The total production in the years 1997 and 1999
    100

    ⇒
    150 × X
    		= 155
    100

    ⇒ X =
    155 × 100
    		 =
    310
    1503

    X = 103
    1
    3

  1. The ratio of the total production of fertilizers in the year 1995, 1997 and 1999 to the total production in the remaining three years is








  1. View Hint View Answer Discuss in Forum

    As per the given bar graph in question ,
    Total production of fertilizers in the year 1995, 1997 and 1999 = 70 + 90 + 60 = 220
    Total production of fertilizers in the year 1996, 1998 and 2000 = 80 + 80 + 75 = 235
    Required ratio = Total production of fertilizers in the year 1995, 1997 and 1999 : Total production of fertilizers in the year 1996, 1998 and 2000

    Correct Option: C

    As per the given bar graph in question ,
    Total production of fertilizers in the year 1995, 1997 and 1999 = 70 + 90 + 60 = 220
    Total production of fertilizers in the year 1996, 1998 and 2000 = 80 + 80 + 75 = 235
    Required ratio = Total production of fertilizers in the year 1995, 1997 and 1999 : Total production of fertilizers in the year 1996, 1998 and 2000
    ∴ Required ratio = 220 : 235 = 44 : 47

  1. The difference of the average production of fertilizers in the first three years and the average production in the last three years (in lakh tonnes) is








  1. View Hint View Answer Discuss in Forum

    On the basis of given graph in question ,
    Production of fertilizers in 1995 = 70
    Production of fertilizers in 1996 = 80
    Production of fertilizers in 1997 = 90
    Production of fertilizers in 1998 = 80
    Production of fertilizers in 1999 = 60
    Production of fertilizers in 2000 = 75
    Sum of production of fertilizers in the first three years = 70 + 80 + 90 = 240 lakh tonnes
    Sum of production of fertilizers in the last three years = 80 + 60 + 75 = 215 lakh tonnes

    Required difference =
    1
    		[(Sum of production of fertilizers in the first three years – Sum of production of fertilizers in the last three years)]
    3

    Required difference =
    1
    		[(240 – 215)] lakh tonnes
    3

    Correct Option: B

    On the basis of given graph in question ,
    Production of fertilizers in 1995 = 70
    Production of fertilizers in 1996 = 80
    Production of fertilizers in 1997 = 90
    Production of fertilizers in 1998 = 80
    Production of fertilizers in 1999 = 60
    Production of fertilizers in 2000 = 75
    Sum of production of fertilizers in the first three years = 70 + 80 + 90 = 240 lakh tonnes
    Sum of production of fertilizers in the last three years = 80 + 60 + 75 = 215 lakh tonnes

    Required difference =
    1
    		[(Sum of production of fertilizers in the first three years – Sum of production of fertilizers in the last three years)]
    3

    Required difference =
    1
    		[(240 – 215)] lakh tonnes
    3

    Required difference =
    25
    		lakh tonnes
    3

    Required difference = 8
    1
    		lakh tonnes
    3

Direction: Read the following graph and answer questions

  1. The deficit in 1992-93 was approximately how many percent of the average deficit?








  1. View Hint View Answer Discuss in Forum

    As per the given bar graph in question ,
    The deficit in 1992-93 = 3600

    Average deficit =
    23200
    		 = 2900 million
    8

    Required percentage =
    The deficit in 1992-93
    		× 100
    Average deficit

    Correct Option: C

    As per the given bar graph in question ,
    The deficit in 1992-93 = 3600

    Average deficit =
    23200
    		 = 2900 million
    8

    Required percentage =
    The deficit in 1992-93
    		× 100
    Average deficit

    Required percentage =
    3600
    		× 100 ≈ 125%
    2900