## Introduction to Data Interpretation

#### Data Interpretation

Direction: The following bar graph shows the production of fertilizers (in lakh tonnes) by a company, in six consecutive years. Study the graph and answer the questions. 1. The year in which the production of fertilizers is nearest to the average production of all the six years, is

1. According to given bar graph in question ,
Sum of the production of fertilizers all six years = 70 + 80 + 90 + 80 + 60 + 75 = 455 lakh tonnes
Total number of years = 6

 In year 2000 average production of fertilizers = 455 = 75 5 lakh tonnes 6 6

##### Correct Option: D

According to given bar graph in question ,
Sum of the production of fertilizers all six years = 70 + 80 + 90 + 80 + 60 + 75 = 455 lakh tonnes
Total number of years = 6

 In year 2000 average production of fertilizers = 455 = 75 5 lakh tonnes 6 6

Hence , required answer is 2000 year .

1. The total production of fertilizers in the year 1998 and 2000 is X% of the total production in the years 1997 and 1999. Then X is equal to

1. On the basis of given graph in question , we have
The total production of fertilizers in the year 1998 and 2000 = ( 90 + 60 ) = 150
The total production in the years 1997 and 1999 = ( 80 + 75 ) = 155

 The total production of fertilizers in the year 1998 and 2000 × X = The total production in the years 1997 and 1999 100

 ⇒ 150 × X = 155 100

 ⇒ X = 155 × 100 = 310 150 3

##### Correct Option: A

On the basis of given graph in question , we have
The total production of fertilizers in the year 1998 and 2000 = ( 90 + 60 ) = 150
The total production in the years 1997 and 1999 = ( 80 + 75 ) = 155

 The total production of fertilizers in the year 1998 and 2000 × X = The total production in the years 1997 and 1999 100

 ⇒ 150 × X = 155 100

 ⇒ X = 155 × 100 = 310 150 3

 X = 103 1 3

1. The ratio of the total production of fertilizers in the year 1995, 1997 and 1999 to the total production in the remaining three years is

1. As per the given bar graph in question ,
Total production of fertilizers in the year 1995, 1997 and 1999 = 70 + 90 + 60 = 220
Total production of fertilizers in the year 1996, 1998 and 2000 = 80 + 80 + 75 = 235
Required ratio = Total production of fertilizers in the year 1995, 1997 and 1999 : Total production of fertilizers in the year 1996, 1998 and 2000

##### Correct Option: C

As per the given bar graph in question ,
Total production of fertilizers in the year 1995, 1997 and 1999 = 70 + 90 + 60 = 220
Total production of fertilizers in the year 1996, 1998 and 2000 = 80 + 80 + 75 = 235
Required ratio = Total production of fertilizers in the year 1995, 1997 and 1999 : Total production of fertilizers in the year 1996, 1998 and 2000
∴ Required ratio = 220 : 235 = 44 : 47

1. The difference of the average production of fertilizers in the first three years and the average production in the last three years (in lakh tonnes) is

1. On the basis of given graph in question ,
Production of fertilizers in 1995 = 70
Production of fertilizers in 1996 = 80
Production of fertilizers in 1997 = 90
Production of fertilizers in 1998 = 80
Production of fertilizers in 1999 = 60
Production of fertilizers in 2000 = 75
Sum of production of fertilizers in the first three years = 70 + 80 + 90 = 240 lakh tonnes
Sum of production of fertilizers in the last three years = 80 + 60 + 75 = 215 lakh tonnes

 Required difference = 1 [(Sum of production of fertilizers in the first three years – Sum of production of fertilizers in the last three years)] 3

 Required difference = 1 [(240 – 215)] lakh tonnes 3

##### Correct Option: B

On the basis of given graph in question ,
Production of fertilizers in 1995 = 70
Production of fertilizers in 1996 = 80
Production of fertilizers in 1997 = 90
Production of fertilizers in 1998 = 80
Production of fertilizers in 1999 = 60
Production of fertilizers in 2000 = 75
Sum of production of fertilizers in the first three years = 70 + 80 + 90 = 240 lakh tonnes
Sum of production of fertilizers in the last three years = 80 + 60 + 75 = 215 lakh tonnes

 Required difference = 1 [(Sum of production of fertilizers in the first three years – Sum of production of fertilizers in the last three years)] 3

 Required difference = 1 [(240 – 215)] lakh tonnes 3

 Required difference = 25 lakh tonnes 3

 Required difference = 8 1 lakh tonnes 3 1. The deficit in 1992-93 was approximately how many percent of the average deficit?

1. As per the given bar graph in question ,
The deficit in 1992-93 = 3600

 Average deficit = 23200 = 2900 million 8

 Required percentage = The deficit in 1992-93 × 100 Average deficit

##### Correct Option: C

As per the given bar graph in question ,
The deficit in 1992-93 = 3600

 Average deficit = 23200 = 2900 million 8

 Required percentage = The deficit in 1992-93 × 100 Average deficit

 Required percentage = 3600 × 100 ≈ 125% 2900