## Introduction to Data Interpretation

#### Data Interpretation

Direction: The graph given here shows a car following the linear path with uniform speed. Study the graph and answer the questions. 1. The speed of the car (in metres per minute) is

1. According to given graph in question ,
Speed = 6 kmph
We convert kmph into metre per minute

##### Correct Option: B

According to given graph in question ,
Speed = 6 kmph
We convert kmph into metre per minute

 Speed = 6 × 1000 m/min. = = 100m/min. 60

1. The speed of the car is

1. As per the given graph in question ,
The car covers 6 km in 1 hour.
Distance = 6 km , Time = 1 hour

 ∴ Speed = Distance Time

##### Correct Option: B

As per the given graph in question ,
The car covers 6 km in 1 hour.
Distance = 6 km , Time = 1 hour

 ∴ Speed = Distance Time

 ∴ Speed = 6 = 6 kmph 1

Direction: The graph given here shows the annual premiums of an insurance company, charged for an insurance of \$ 1000 for individuals of different age groups. Study the graph and answer each of the following questions : 1. Each of two persons aged 21 years and 23 years is insured for \$ 1,00,000. The difference between their annual premiums will be

1. According to given graph in question ,
Required difference = (44 - 43.50) × 100

##### Correct Option: B

According to given graph in question ,
Required difference = (44 - 43.50) × 100
Required difference = 0.50 × 100 = \$ 50

1. What percent of the premium is increased if a managed 30 years is insured for \$ 1000 instead of a managed 23 years?

1. As per the given graph in question ,

 Required increase = 46.544 × 100 44

##### Correct Option: B

As per the given graph in question ,

 Required increase = 46.544 × 100 = 5.68% 44

1. The premium for a managed 22 years for an insurance of \$ 10,000 is

1. From the given graph in question ,
Required premium = 43·75 × 10

##### Correct Option: D

From the given graph in question ,
Required premium = 43·75 × 10 = 437·5
Hence , The premium for a managed 22 years for an insurance of \$ 10,000 is \$ 437·5 .