Introduction to Data Interpretation
Direction: The sub divided bar diagram given below depicts H.S. Students of a school for three years. Study the diagram and answer the questions.
- The number of students passed with 3rd division in the year 2008 was
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According to given bar graph , we have
Number of students passed in 2nd and 1st division in 2008 = 80
Total number of students passed in 2008 = 140
∴ Students passed in third division in 2008 = Total number of students passed in 2008 - Number of students passed in 2nd and 1st division in 2008Correct Option: B
According to given bar graph , we have
Number of students passed in 2nd and 1st division in 2008 = 80
Total number of students passed in 2008 = 140
∴ Students passed in third division in 2008 = Total number of students passed in 2008 - Number of students passed in 2nd and 1st division in 2008
Students passed in third division in 2008 = 140 – 80 = 60
- In which year the school had the best result for H.S. in respect of percentage of pass candidates?
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On the basis of given graph in question ,
Total students who passed in 2008 = 140
Total students in 2008 = 170
Year 2008 ⇒∴ Required percentage = 140 × 100 170 Required percentage = 82 6 % 11
Year 2009 ⇒
Total students who passed in 2009 = 140
Total students in 2009 = 190Required percentage = 140 × 100 = 73.7% 190
Correct Option: A
On the basis of given graph in question ,
Total students who passed in 2008 = 140
Total students in 2008 = 170
Year 2008 ⇒∴ Required percentage = 140 × 100 170 Required percentage = 82 6 % 11
Year 2009 ⇒
Total students who passed in 2009 = 140
Total students in 2009 = 190Required percentage = 140 × 100 = 73.7% 190
Year 2010 ⇒
Total students who passed in 2010 = 150
Total students in 2010 = 200Required percentage = 150 × 100 = 75% 200
Hence , required answer is 2008 year .
- The pass percentage in 2008 was
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View Hint View Answer Discuss in Forum
On the basis of given graph in question ,
Total students who passed in 2008 = 140
Total students in 2008 = 170∴ Required percentage = 140 × 100 170
Correct Option: D
On the basis of given graph in question ,
Total students who passed in 2008 = 140
Total students in 2008 = 170∴ Required percentage = 140 × 100 170 Required percentage = 1400 = 82 6 % 17 17
- The percentage passed in 1st division in 2008 was
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View Hint View Answer Discuss in Forum
According to given bar graph , we have
Total students in 2008 = 170
Students passed in 1st division = 20∴ Required percentage = Students passed in 1st division × 100 Total students in 2008 Required percentage = 20 × 100 170
Correct Option: D
According to given bar graph , we have
Total students in 2008 = 170
Students passed in 1st division = 20∴ Required percentage = Students passed in 1st division × 100 Total students in 2008 Required percentage = 20 × 100 170 Required percentage = 200 = 11 13 % 17 17
Direction: The bar chart given below shows the percentage distribution of the production of various models of a mobile manufacturing company in 2007 and 2008. The total production in 2007 was 35 lakh mobile phones and in 2008 the production was 44 lakh. Study the chart and answer the following questions.
- If 85% of the D type mobiles produced in each year were sold by the company, how many D type mobiles remained unsold?
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View Hint View Answer Discuss in Forum
On the basis of given graph in question ,
Given , The total production in 2007 = 35 lakh mobile phones
The total production in 2008 = 44 lakh mobile phones
Percent of mobiles of models D manufactured in 2007 = 10%
Percent of mobiles of models D manufactured in 2008 = 10%
Required answer = 10% of ( 100 - 85 )% of 35 + 10% of ( 100 - 85 )% of 44Required answer = 35 × 10 × 15 + 44 × 10 × 15 100 100 100 100
Correct Option: C
On the basis of given graph in question ,
Given , The total production in 2007 = 35 lakh mobile phones
The total production in 2008 = 44 lakh mobile phones
Percent of mobiles of models D manufactured in 2007 = 10%
Percent of mobiles of models D manufactured in 2008 = 10%
Required answer = 10% of ( 100 - 85 )% of 35 + 10% of ( 100 - 85 )% of 44Required answer = 35 × 10 × 15 + 44 × 10 × 15 100 100 100 100 Required answer = 150 × 79 = 1.1850 billion = 118500 10000