Time and Work
- A work can be completed by P and Q in 12 days, Q and R in 15 days, R and P in 20 days. In how many days P alone can finish the work?
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(P + Q)’s 1 day’s work = 1 .......(i) 12 (Q + R)’s 1 day’s work = 1 .......(ii) 15 (R + P)’s 1 day’s work = 1 .......(iii) 20
Adding all three equations,2 (P + Q + R)’s 1 day’s work = 1 + 1 + 1 12 15 20
Correct Option: C
(P + Q)’s 1 day’s work = 1 .......(i) 12 (Q + R)’s 1 day’s work = 1 .......(ii) 15 (R + P)’s 1 day’s work = 1 .......(iii) 20
Adding all three equations,2 (P + Q + R)’s 1 day’s work = 1 + 1 + 1 12 15 20 2 (P + Q + R)’s 1 day’s work = 5 + 4 + 3 = 1 60 5 ∴ (P + Q + R)’s 1 day’s work = 1 .......(iv) 10 ∴ P’s 1 day’s work = 1 - 1 10 15 P’s 1 day’s work = 3 - 2 = 1 30 30
∴ P alone will complete the work in 30 days.
- A and B can complete a piece of work in 8 days, B and C can do it in 12 days, C and A can do it in 8 days. A, B and C together can complete it in
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(A + B)’s 1 day’s work = 1 8 (B + C)’s 1 day’s work = 1 12 (C + A)’s 1 day’s work = 1 8
On adding ,2 (A + B + C)’s 1 day’s work = 1 + 1 + 1 8 12 8 2 (A + B + C)’s 1 day’s work = 3 + 2 + 3 24 2 (A + B + C)’s 1 day’s work = 8 = 1 24 3
∴ (A + B + C)’s 1 day’s work = 1 6
Hence, the work will be completed in 6 days.
2nd Method to solve this question :
Correct Option: C
(A + B)’s 1 day’s work = 1 8 (B + C)’s 1 day’s work = 1 12 (C + A)’s 1 day’s work = 1 8
On adding ,2 (A + B + C)’s 1 day’s work = 1 + 1 + 1 8 12 8 2 (A + B + C)’s 1 day’s work = 3 + 2 + 3 24 2 (A + B + C)’s 1 day’s work = 8 = 1 24 3
∴ (A + B + C)’s 1 day’s work = 1 6
Hence, the work will be completed in 6 days.
2nd Method to solve this question :Time = 2xyz xy + yz + zx
Here, x = 8, y = 12; z = 8Time = 2 × 8 × 12 × 8 = 2 × 8 × 12 × 8 = 6 days 96 + 96 + 64 256
- 'A' can do a piece of work in x days and B can do the same work 3x days. To finish the work together they take 12 days. What is the value of x ?
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View Hint View Answer Discuss in Forum
A's 1 day's work A = 1/x
B's 1 day's work B = 1/3x
(A + B)'s 1 day's work = (1/x) + (1/3x) = 4/3x
And given one day work of both A and B = 1/12
⇒ 4/3x = 1/12Correct Option: D
A's 1 day's work A = 1/x
B's 1 day's work B = 1/3x
(A + B)'s 1 day's work = (1/x) + (1/3x) = 4/3x
And given one day work of both A and B = 1/12
⇒ 4/3x = 1/12
⇒ 3x = 48
⇒ x =16
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A and B working together; can do a piece of work in 4 1 hours. B and C working together 2
begin the work at the same time. Find how much time they will take to finish the piece of work.can do it in 3 hours. C and A working together can do it in 2 1 hours. All of them 4
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View Hint View Answer Discuss in Forum
(A + B)’s 1 hour’s work = 2 .......(i) 9 (B + C)’s 1 hour’s work = 1 .......(ii) 3 (C + A)’s 1 hour’s work = 4 .......(iii) 9
Adding all three equations,2 (A + B + C)’s 1 hour’s work = 2 + 1 + 4 9 3 9 2 (A + B + C)’s 1 hour’s work = 2 + 3 + 4 = 1 9
∴ A, B and C together will complete the work in 2 hours.
Second method to solve this question ,
Here , x = 9 / 2 , y = 3 , z = 9 / 4
Correct Option: B
(A + B)’s 1 hour’s work = 2 .......(i) 9 (B + C)’s 1 hour’s work = 1 .......(ii) 3 (C + A)’s 1 hour’s work = 4 .......(iii) 9
Adding all three equations,2 (A + B + C)’s 1 hour’s work = 2 + 1 + 4 9 3 9 2 (A + B + C)’s 1 hour’s work = 2 + 3 + 4 = 1 9
∴ A, B and C together will complete the work in 2 hours.
Second method to solve this question ,
Here , x = 9 / 2 , y = 3 , z = 9 / 4Time taken = 2 × 9 × 3 × 9 2 4 9 × 3 + 3 × 9 + 9 × 9 2 4 2 4 Time taken = ( 18 × 27 ) / 8 { ( 27/2 ) + ( 27/4 ) + ( 81/8 ) } Time taken = 18 × 27 × 8 8 ( 108 + 54 + 81 ) Time taken = 18 × 27 = 2 hours 243
- A and B together can complete a piece of work in 18 days, B and C in 24 days and A and C in 36 days. In how many days, will all of them together complete the work ?
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View Hint View Answer Discuss in Forum
(A + B)’s 1 day’s work = 1 18
(B + C)’s 1 day’s work = 1 24 (A + C)’s 1 day’s work = 1 36
Adding all three,2 (A + B + C)’s 1 day’s work = 1 + 1 + 1 18 24 36 2 (A + B + C)’s 1 day’s work = 4 + 3 + 2 = 1 72 8 ∴ (A + B + C)’ 1 day’s work = 1 16
∴ A, B and C together will complete the work in 16 days.
Second method to solve this question ,
Here , x = 18 , y = 24 , z = 36Time taken = 2xyz xy + yz + zx
Correct Option: A
(A + B)’s 1 day’s work = 1 18
(B + C)’s 1 day’s work = 1 24 (A + C)’s 1 day’s work = 1 36
Adding all three,2 (A + B + C)’s 1 day’s work = 1 + 1 + 1 18 24 36 2 (A + B + C)’s 1 day’s work = 4 + 3 + 2 = 1 72 8 ∴ (A + B + C)’ 1 day’s work = 1 16
∴ A, B and C together will complete the work in 16 days.
Second method to solve this question ,
Here , x = 18 , y = 24 , z = 36Time taken = 2xyz xy + yz + zx Total time taken = 2 × 18 × 24 × 36 18 × 24 + 24 × 36 + 36 × 18 Total time taken = 36 × 24 × 36 432 + 864 + 648 Total time taken = 31104 = 16 days 1944