Time and Work
- A is twice as good a workman as B and together they finish a piece of work in 14 days. In how many days can a alone finish the work?
-
View Hint View Answer Discuss in Forum
One day's work of A and B = 1/x + 1/2x = 1/14
∴ x = 21Correct Option: C
One day's work of A and B = 1/x + 1/2x = 1/14
∴ x = 21
Since A is twice efficient as B so A will take half of the day taken by B.
- A can do a piece of work in 24 days. If B is 60% more efficient than A, then the number of days required by B to do the same piece of work is ?
-
View Hint View Answer Discuss in Forum
Efficiency of A = 4.16%
Efficiency of B = 1.6 x 4.16 = 6.66%Correct Option: B
Efficiency of A = 4.16%
Efficiency of B = 1.6 x 4.16 = 6.66%
∴ Number of days required by B = 100/6.66 = 15 days
- A can do a piece of work in 14 days while B can do it in 21 days. In how many days, working together they will complete the whole work?
-
View Hint View Answer Discuss in Forum
One day's work of A and B = 1/14 + 1/21 = 5/42
Correct Option: C
One day's work of A and B = 1/14 + 1/21 = 5/42
∴ Required number of days = 42/5 = 8.4 days
- A can finish a piece of work in 12 days while B can do it in 15 days. If both work at it together, what time will they take to do the work?
-
View Hint View Answer Discuss in Forum
Efficiency of A = 100/12 = 8.33%
Efficiency of B = 100/15 = 6.66%
Combined efficiency of A and B = 8.33 + 6.66 = 15%Correct Option: C
Efficiency of A = 100/12 = 8.33%
Efficiency of B = 100/15 = 6.66%
Combined efficiency of A and B = 8.33 + 6.66 = 15%
Number of days taken by A and B, when worked together = 100/15
= 62/3 days
- A can do a piece of work in 12 days. B is 60% more efficient than A. The number of days, it take B to do the same piece of work is ?
-
View Hint View Answer Discuss in Forum
A's 1 day's work = 1/12
B's 1 day's work = 1/12 + 60% of 1/12 = 1/12 x 160/100 = 2/15Correct Option: A
A's 1 day's work = 1/12
B's 1 day's work = 1/12 + 60% of 1/12 = 1/12 x 160/100 = 2/15
∴ B can do the work in 15/2 days = 71/2 days.
