Time and Work
- Rohan and Sunil separately can complete a work in 8 hours and 4 hours respectively. How much time will they take when working together ?
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Required time taken to complete the work by both together = x y / x + y
(Here x = 8 and y = 4)Correct Option: A
Required time taken to complete the work by both together = x y / x + y
(Here x = 8 and y = 4)
∴ Required time = (8 x 4)/(8 + 4) = 32/12 = 22/3 hours
- A and B together can do a work in 8 days. If A alone can do it in 12 days, then in how many days can B alone do it ?
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Required time taken by B to complete the work = xy / x - y
[Here x = 12 and y = 8]Correct Option: C
Required time taken by B to complete the work = xy / x - y
[Here x = 12 and y = 8]
⇒ required time = (12 x 8) / (12 - 8) = 96/4 = 24 days
- A can do a piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in ?
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B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4Correct Option: B
B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/4 work is done by A in = 20 x (1/4) = 5 days.
- A can do (1/3) of a work in 5 days and B can do (2/5) of the work in 10 days. In how many days both A and B together can do the work ?
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∵ 1/3 of work is done by A in 5 days.
∴ Whole work will be done by A in 15 days.
∵ 2/3 of work is done by B in 10 days.
Whole work will be done by B in 10 x (5/2) i.e., 25daysCorrect Option: C
∵ 1/3 of work is done by A in 5 days.
∴ Whole work will be done by A in 15 days.
∵ 2/3 of work is done by B in 10 days.
Whole work will be done by B in 10 x (5/2) i.e., 25days
∴ (A + B)'s 1 day's work = (1/15 + 1/25) = 8/75
So, both together can finish it in 75/8 days, i.e., 93/8days.
- A can do a piece of work in 30 days while B can do it in 40 days. In how many days can A and B working together do it ?
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(A + B)'s 1 day's work = (1/30 + 1/40) = 7/120
Correct Option: D
(A + B)'s 1 day's work = (1/30 + 1/40) = 7/120
∴ Time taken by both to finish the work = 120/7days = 171/7 days