Time and Work


  1. A can do a work in 12 days. When he had worked for 3 days, B joined him. If they complete the work in 3 more days, in how many days can B alone finish the work?









  1. View Hint View Answer Discuss in Forum

    Let B alone do the work in x days.

    ∴ 6 ×
    1
    + 3 ×
    1
    = 1
    12x

    1
    +
    3
    = 1
    2x

    3
    =
    1
    ⇒ x = 6 days
    x2

    Correct Option: A

    Let B alone do the work in x days.

    ∴ 6 ×
    1
    + 3 ×
    1
    = 1
    12x

    1
    +
    3
    = 1
    2x

    3
    =
    1
    ⇒ x = 6 days
    x2


  1. A road of 5 km length will be constructed in 100 days. So 280 workers were employed. But after 80 days it was found that only
    3
    1
    km road was completed.
    2

    Now how many more people were needed to finish the work in the specified time ?









  1. View Hint View Answer Discuss in Forum

    Using Rule 1,
    Remaining work

    = 5 –
    7
    =
    3
    22

    M1 × D1 × W2 = M2 × D2 × W1
    ⇒ 280 × 80 ×
    3
    2

    = M2 × 20 ×
    7
    2

    ⇒ M2 =
    280 × 80 × 3
    = 480
    20 × 7

    ∴ Required number of additional men = 480 – 280 = 200

    Correct Option: C

    Using Rule 1,
    Remaining work

    = 5 –
    7
    =
    3
    22

    M1 × D1 × W2 = M2 × D2 × W1
    ⇒ 280 × 80 ×
    3
    2

    = M2 × 20 ×
    7
    2

    ⇒ M2 =
    280 × 80 × 3
    = 480
    20 × 7

    ∴ Required number of additional men = 480 – 280 = 200



  1. Ganga and Saraswati, working separately can mow a field in 8 and 12 hours respectively. If they work in stretches of one hour alternately, Ganga beginning at 9 a.m., when will the moving be completed ?









  1. View Hint View Answer Discuss in Forum

    Part of the field mowed by
    Ganga and Saraswati in first 2 hours

    =
    1
    +
    1
    =
    3 + 2
    =
    5
    8122424

    ∴ Part of the field mowed in first 8 hours
    =
    5 × 4
    =
    20
    =
    5
    24246

    Remaining work
    = 1 -
    5
    =
    1
    66

    Now, it is the turn of Ganga, part of work done by Ganga in 1 hour
    =
    1
    8

    Remaining work
    =
    1
    -
    1
    68

    =
    4 - 3
    =
    1
    2424

    Now, time taken by Saraswati in completing this part of work
    =
    1
    × 12 =
    1
    hour
    242

    ∴ Total time = 9
    1
    hours
    2

    The mowing starts at 9 am.
    Hence, the mowing will be completed at 6.30 pm.

    Correct Option: B

    Part of the field mowed by
    Ganga and Saraswati in first 2 hours

    =
    1
    +
    1
    =
    3 + 2
    =
    5
    8122424

    ∴ Part of the field mowed in first 8 hours
    =
    5 × 4
    =
    20
    =
    5
    24246

    Remaining work
    = 1 -
    5
    =
    1
    66

    Now, it is the turn of Ganga, part of work done by Ganga in 1 hour
    =
    1
    8

    Remaining work
    =
    1
    -
    1
    68

    =
    4 - 3
    =
    1
    2424

    Now, time taken by Saraswati in completing this part of work
    =
    1
    × 12 =
    1
    hour
    242

    ∴ Total time = 9
    1
    hours
    2

    The mowing starts at 9 am.
    Hence, the mowing will be completed at 6.30 pm.


  1. If two persons, with equal abilities, can do two jobs in two days, then 100 persons with equal abilities can do 100 similar jobs in









  1. View Hint View Answer Discuss in Forum

    According to the question,
    2 persons with equal abilities can do 1 job in 1 day
    ∴ Time taken by 1 man to complete 1 job = 2 days
    ⇒ Time taken by 100 persons in completing 100 jobs = 2 days

    Correct Option: D

    According to the question,
    2 persons with equal abilities can do 1 job in 1 day
    ∴ Time taken by 1 man to complete 1 job = 2 days
    ⇒ Time taken by 100 persons in completing 100 jobs = 2 days



  1. A and B can do a piece of work in 30 days while B and C can do the same work in 24 days and C and A in 20 days. They all work for 10 days when B and C leave.
    How many days more will A take to complete the work?









  1. View Hint View Answer Discuss in Forum

    Using Rule 3,

    (A + B)’s 1 day’s work =
    1
    30

    (B + C)’s 1 day’s work =
    1
    24

    (C + A)’s 1 day’s work =
    1
    20

    Adding all the above, we have
    2 ( A + B + C)’s 1 day’s work
    =
    1
    +
    1
    +
    1
    302420

    =
    4 + 5 + 6
    =
    15
    =
    1
    1201208

    ∴ (A + B + C)’s 1 day’s work
    =
    1
    =
    1
    8 × 216

    Now, all three worked together for 10 days.
    ∴ (A + B + C)’s 10 days’ work
    =
    1
    × 10 =
    5
    168

    ∴ Remaining part of work
    = 1 -
    5
    =
    8 - 5
    =
    3
    888

    Now, A’s 1 day’s work
    =
    1
    -
    1
    =
    3 - 2
    =
    1
    16244848

    Since, A finishes 1/48 part of work in 1 day
    ∴ A will finish 3/8 part of work in
    1 × 48 ×
    3
    = 18 days.
    8

    Correct Option: C

    Using Rule 3,

    (A + B)’s 1 day’s work =
    1
    30

    (B + C)’s 1 day’s work =
    1
    24

    (C + A)’s 1 day’s work =
    1
    20

    Adding all the above, we have
    2 ( A + B + C)’s 1 day’s work
    =
    1
    +
    1
    +
    1
    302420

    =
    4 + 5 + 6
    =
    15
    =
    1
    1201208

    ∴ (A + B + C)’s 1 day’s work
    =
    1
    =
    1
    8 × 216

    Now, all three worked together for 10 days.
    ∴ (A + B + C)’s 10 days’ work
    =
    1
    × 10 =
    5
    168

    ∴ Remaining part of work
    = 1 -
    5
    =
    8 - 5
    =
    3
    888

    Now, A’s 1 day’s work
    =
    1
    -
    1
    =
    3 - 2
    =
    1
    16244848

    Since, A finishes 1/48 part of work in 1 day
    ∴ A will finish 3/8 part of work in
    1 × 48 ×
    3
    = 18 days.
    8