A can do a work in 12 days. When he had worked for 3 days,

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A can do a work in 12 days. When he had worked for 3 days, B joined him. If they complete the work in 3 more days, in how many days can B alone finish the work?

Let B alone do the work in x days.

∴ 6 ×	1	+ 3 ×	1	= 1
	12		x

⇒	1	+	3	= 1
	2		x

⇒	3	=	1	⇒ x = 6 days
	x		2