Time and Work


  1. A can finish a work in 7 days. B can finish the same work in 9 days. The number days required to finish the same work by both of them together is









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    A’s 1 day’s work =
    1
    7

    B’s 1 day’s work =
    1
    9

    ∴ (A + B)’s 1 day’s work
    =
    1
    +
    1
    79

    =
    1440
    =
    40
    = 3
    1
    days
    4681313

    ∴ Required time =
    63
    days
    16

    = 3
    15
    days
    16

    Correct Option: C

    A’s 1 day’s work =
    1
    7

    B’s 1 day’s work =
    1
    9

    ∴ (A + B)’s 1 day’s work
    =
    1
    +
    1
    79

    =
    1440
    =
    40
    = 3
    1
    days
    4681313

    ∴ Required time =
    63
    days
    16

    = 3
    15
    days
    16


  1. A, B and C working separately can do a piece of work in 11 days, 20 days and 55 days respectively. In how many days, the work will be completed if A is assisted by B and C on alternate days ?









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    (A + B)’s 1 day’s work

    =
    1
    +
    1
    1120

    =
    20 + 11
    =
    31
    220220

    (A + C)’s 1 day’s work
    =
    1
    +
    1
    1155

    =
    5 + 1
    =
    6
    5555

    Work done in first two days
    =
    31
    +
    6
    22055

    =
    31 + 24
    =
    55
    =
    1
    2202204

    ∴ Required time = 2 × 4 = 8 days

    Correct Option: D

    (A + B)’s 1 day’s work

    =
    1
    +
    1
    1120

    =
    20 + 11
    =
    31
    220220

    (A + C)’s 1 day’s work
    =
    1
    +
    1
    1155

    =
    5 + 1
    =
    6
    5555

    Work done in first two days
    =
    31
    +
    6
    22055

    =
    31 + 24
    =
    55
    =
    1
    2202204

    ∴ Required time = 2 × 4 = 8 days



  1. A can do a piece of work in 12 days and B in 24 days. If they work together, in how many days will they finish the work?









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    (A + B)’s 1 day’s work

    =
    1
    +
    1
    1224

    =
    2 + 1
    =
    3
    =
    1
    24248

    ∴ Required time = 8 days

    Correct Option: D

    (A + B)’s 1 day’s work

    =
    1
    +
    1
    1224

    =
    2 + 1
    =
    3
    =
    1
    24248

    ∴ Required time = 8 days


  1. A and B together can finish a job in 24 days, while A, B and C together can finish the same job in 8 days. C alone will finish the job in









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    (A + B)’s 1 day’s work =
    1
    24

    (A + B + C)’s 1 day’s work =
    1
    6

    ∴ C’s 1 day’s work =
    1
    -
    1
    824

    =
    3 - 1
    =
    2
    =
    1
    242412

    ∴ Required time = 12 days

    Correct Option: A

    (A + B)’s 1 day’s work =
    1
    24

    (A + B + C)’s 1 day’s work =
    1
    6

    ∴ C’s 1 day’s work =
    1
    -
    1
    824

    =
    3 - 1
    =
    2
    =
    1
    242412

    ∴ Required time = 12 days



  1. A and B together can do a piece of work in 6 days and A alone can do it in 9 days. The number of days B will take to do it alone is









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    (A + B)’s 1 day’s work =
    1
    6

    A’s 1 day’s work =
    1
    9

    ∴ B’s 1 day’s work =
    1
    -
    1
    69

    =
    3 - 2
    =
    1
    1818

    ∴ Required time = 18 days

    Correct Option: A

    (A + B)’s 1 day’s work =
    1
    6

    A’s 1 day’s work =
    1
    9

    ∴ B’s 1 day’s work =
    1
    -
    1
    69

    =
    3 - 2
    =
    1
    1818

    ∴ Required time = 18 days