Time and Work
- Janardan completes 2/3 of his work in 10 days. Time he will take to complete 3/5 of the same work, is
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Using Rule 1,
M1D1 = M2D2 W1 W2 = 10 ⇒ D2 2/5 3/5 ⇒ 30 = 5D2 2 3 ⇒ D2 = 30 × 3 = 9 days 2 5 Correct Option: C
Using Rule 1,
M1D1 = M2D2 W1 W2 = 10 ⇒ D2 2/5 3/5 ⇒ 30 = 5D2 2 3 ⇒ D2 = 30 × 3 = 9 days 2 5
- A contractor was engaged to construct a road in 16 days. After working for 12 days with 20 labours it was found that only 5/8 th of the road had been constructed. To complete the work in stipulated time the number of extra labours required is :
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Using Rule 1,
Remaining work= 1 - 5 = 3 ; 8 8
Remaining time = 4 daysM1D1 = M2D2 W1 W2 = 20 × 12 = M2 × 4 5/8 3/8 = 20 × 12 = M2 × 4 5 3 ⇒ 4 × 12 = M2 × 4 3
⇒ M2 = 12 × 3 = 36
∴ Number of additional workers
= 36 – 20 = 16Correct Option: D
Using Rule 1,
Remaining work= 1 - 5 = 3 ; 8 8
Remaining time = 4 daysM1D1 = M2D2 W1 W2 = 20 × 12 = M2 × 4 5/8 3/8 = 20 × 12 = M2 × 4 5 3 ⇒ 4 × 12 = M2 × 4 3
⇒ M2 = 12 × 3 = 36
∴ Number of additional workers
= 36 – 20 = 16
- If 12 men working 8 hours a day complete the work in 10 days, how long would 16 men working
hours a day take to complete the same work?7 1 2
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Using Rule 1,
⇒ 16 × 15 × x = 12 × 8 × 10 2
⇒ 8 × 15 × x = 12 × 8 × 10⇒ x = 12 × 8 × 10 = 8 days 8 × 15 Correct Option: D
Using Rule 1,
⇒ 16 × 15 × x = 12 × 8 × 10 2
⇒ 8 × 15 × x = 12 × 8 × 10⇒ x = 12 × 8 × 10 = 8 days 8 × 15
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Jyothi can do 3 of a job in 12 4
days. Mala is twice as efficient as Jyothi. In how many days will Mala finish the job ?
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Using Rule 1,
∵ Jyothi can do 3 th of a job in 12 days 4
∴ Jyothi can do 1 job in12 × 4 = 16 days 3
As Mala is twice as efficient as Jyothi,
∴ Mala will finish the job in 8 daysCorrect Option: B
Using Rule 1,
∵ Jyothi can do 3 th of a job in 12 days 4
∴ Jyothi can do 1 job in12 × 4 = 16 days 3
As Mala is twice as efficient as Jyothi,
∴ Mala will finish the job in 8 days
- 4 men and 6 women complete a work in 8 days. 2 men and 9 women also complete in 8 days in which. The number of days in which 18 women complete the work is :
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According to the question,
(4 × 8) men + (6 × 8) women ≡ (2 × 8) men + (9 × 8) women
⇒ 4 men + 6 women ≡ 2 men + 9 women
⇒ (4 – 2) men ≡ (9 – 6) women
⇒ 2 men ≡ 3 women
∴ 4 men + 6 women ≡ 12 women
∴ M1D1 = M2D2
⇒ 12 × 8 = 18 × D2⇒ D2 = 12 × 8 18 = 16 = 5 1 days 3 3
Aliter : Using Rule 1,
Here, A1 = 4, B1 = 6, D1 = 8
A2 = 2, B2 = 9, D2 = 8
A3 = 0, B3 = 18
Required time= D1D2(A1B2 - A2B1) D1(A1B3 - A3B1) - D2(A2B3 - A3B2) = 8 × 8(4 × 9 - 2 × 6) 8(4 × 18 - 0 × 6) - 8(2 × 18 - 0 × 6) = 64 × 24 = 192 8 × 72 - 36 × 8 36 = 16 = 5 1 days 3 3 Correct Option: B
According to the question,
(4 × 8) men + (6 × 8) women ≡ (2 × 8) men + (9 × 8) women
⇒ 4 men + 6 women ≡ 2 men + 9 women
⇒ (4 – 2) men ≡ (9 – 6) women
⇒ 2 men ≡ 3 women
∴ 4 men + 6 women ≡ 12 women
∴ M1D1 = M2D2
⇒ 12 × 8 = 18 × D2⇒ D2 = 12 × 8 18 = 16 = 5 1 days 3 3
Aliter : Using Rule 1,
Here, A1 = 4, B1 = 6, D1 = 8
A2 = 2, B2 = 9, D2 = 8
A3 = 0, B3 = 18
Required time= D1D2(A1B2 - A2B1) D1(A1B3 - A3B1) - D2(A2B3 - A3B2) = 8 × 8(4 × 9 - 2 × 6) 8(4 × 18 - 0 × 6) - 8(2 × 18 - 0 × 6) = 64 × 24 = 192 8 × 72 - 36 × 8 36 = 16 = 5 1 days 3 3