Time and Work
- A and B can do a piece of work in 12 days. B and C in 15 days. C and A in 20 days. A alone can do the work in ?
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∵ [(A + B) + (B + C) + (C + A)]'s 1 day's work = (1/12 + 1/15 + 1/20) = 1/5
⇒ 2(A + B + C)'s 1 days work = 1/5
⇒ (A + B + C)'s 1 day's work = 1/10
&rArr A's 1 day's work = (1/10 - 1/15) = 1/30
∴ A alone can finish it in 30 days.Correct Option: C
∵ [(A + B) + (B + C) + (C + A)]'s 1 day's work = (1/12 + 1/15 + 1/20) = 1/5
⇒ 2(A + B + C)'s 1 days work = 1/5
⇒ (A + B + C)'s 1 day's work = 1/10
&rArr A's 1 day's work = (1/10 - 1/15) = 1/30
∴ A alone can finish it in 30 days.
- A and B can do a piece of work in 18 days, B and C in 24 days, A and C in 36 days. In what time can they do it all working together ?
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(A + B)'s 1 day's work = 1/18
(B + C)'s 1 day's work = 1/24
(A + C)'s 1 day's work = 1/36
Adding 2 (A + B + C)'s 1 day's work = (1/18 + 1/24 + 1/36) = 1/8Correct Option: C
(A + B)'s 1 day's work = 1/18
(B + C)'s 1 day's work = 1/24
(A + C)'s 1 day's work = 1/36
Adding 2 (A + B + C)'s 1 day's work = (1/18 + 1/24 + 1/36) = 1/8
∴ (A + B + C)'s day's work = 1/16
Hence, all working together can finish it in 16 days.
- Ajit is 3 times as efficient as Bablu, then the ratio of number of days required by each to work alone, completely?
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Efficiency of Ajit : Bablu = 3 : 1
No. of days 1 : 3Correct Option: B
Efficiency of Ajit : Bablu = 3 : 1
No. of days 1 : 3
- A and B can together do a piece of work in 15 days. B alone can do it 20 days. In how many days can A alone do it ?
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A's 1 day's work = (1/15 - 1/20) = 1/60
Correct Option: D
A's 1 day's work = (1/15 - 1/20) = 1/60
∴ A alone can finish it in 60 days.
- 20 persons completed 1/3rd of the work in 12 days. How many more person are required to finish the rest work in next 12 days?
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Work done = 1/3
Remaining work = 2/3
So for double work in same days we need double number of people i.e. 40.Correct Option: A
Work done = 1/3
Remaining work = 2/3
So for double work in same days we need double number of people i.e. 40.
So, 20 men will be increased.