Time and Work


  1. 36 men together can build a wall 140 m long in 21 days. The number of men working at the same rate required to build the same wall in 14 days is









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    Here, the length of wall is
    same in both cases.
    ∴ M1D1 = M2D2
    ⇒ 36 × 21 = M2 × 14

    ⇒ M2 =
    36 × 21
    = 54 days
    14

    Correct Option: A

    Here, the length of wall is
    same in both cases.
    ∴ M1D1 = M2D2
    ⇒ 36 × 21 = M2 × 14

    ⇒ M2 =
    36 × 21
    = 54 days
    14


  1. The four walls and ceiling of a room of length 25 m, breadth 12 m and height 10 m are to be painted. Painter A can paint 200 m2 in 5 days, Painter B can paint 250 m2 in 2 days. If A and B work together, they will finish the job in









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    Area of the four walls and ceiling of the room
    = 2h (l + b) + lb
    = 2 × 10 (25 + 12) + 25 × 12
    = (20 × 37 + 300) sq. metre
    = (740 + 300) sq. metre
    = 1040 sq. metre
    Area painted by A in 1 day

    =
    200
    = 40 sq. metre
    5

    Area painted by B in 1 day
    =
    250
    = 125 sq. metre
    2

    Area painted by both in1 day
    = (125 + 40) sq. metre
    = 165 sq. metre
    ∴ Required time =
    1040
    165

    =
    208
    = 6
    10
    days
    3333

    Correct Option: B

    Area of the four walls and ceiling of the room
    = 2h (l + b) + lb
    = 2 × 10 (25 + 12) + 25 × 12
    = (20 × 37 + 300) sq. metre
    = (740 + 300) sq. metre
    = 1040 sq. metre
    Area painted by A in 1 day

    =
    200
    = 40 sq. metre
    5

    Area painted by B in 1 day
    =
    250
    = 125 sq. metre
    2

    Area painted by both in1 day
    = (125 + 40) sq. metre
    = 165 sq. metre
    ∴ Required time =
    1040
    165

    =
    208
    = 6
    10
    days
    3333



  1. 20 men working 8 hours per day can complete a piece of work in 21 days. How many hours per day must 48 men work to complete the same job in 7 days?









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    ⇒ 48 × 7 × x = 20 × 21 × 8

    ⇒ x =
    20 × 21 × 8
    = 10 days
    48 × 7

    Correct Option: C


    ⇒ 48 × 7 × x = 20 × 21 × 8

    ⇒ x =
    20 × 21 × 8
    = 10 days
    48 × 7


  1. A group of workers can complete a piece of work in 50 days, when they are working individually. On the first day one person works, on the second day another person joins him, on the third day one more person joins them and this process continues till the work is completed.
    How many approximate days are needed to complete the work?









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    Let the work be finished in x days.

    x
    +
    x - 1
    +
    x - 2
    + ..... +
    1
    = 1
    50505050

    ⇒ x + x – 1 + x – 2 + .... + 1 = 50
    i.e., 10 + 9 + 8 + .... + 1 = 55
    9 + 8 + .... + 1 = 45
    ∴ Required time = 10 days

    Correct Option: C

    Let the work be finished in x days.

    x
    +
    x - 1
    +
    x - 2
    + ..... +
    1
    = 1
    50505050

    ⇒ x + x – 1 + x – 2 + .... + 1 = 50
    i.e., 10 + 9 + 8 + .... + 1 = 55
    9 + 8 + .... + 1 = 45
    ∴ Required time = 10 days



  1. Work done by (x + 4) men in (x + 5) days is equal to the work done by (x – 5) men in (x + 20) days. Then the value of x is









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    Using Rule 1,
    According to the question,
    M1D1 = M2D2
    ⇒ (x + 4) (x + 5)
    = (x – 5) (x + 20)
    ⇒ x2 + 5x + 4x + 20
    = x2 – 5x + 20x – 100
    ⇒ 9x + 20 = 15x – 100
    ⇒ 15x – 9x = 100 + 20
    ⇒ 6x = 120

    ⇒ x =
    120
    = 20
    6

    Correct Option: A

    Using Rule 1,
    According to the question,
    M1D1 = M2D2
    ⇒ (x + 4) (x + 5)
    = (x – 5) (x + 20)
    ⇒ x2 + 5x + 4x + 20
    = x2 – 5x + 20x – 100
    ⇒ 9x + 20 = 15x – 100
    ⇒ 15x – 9x = 100 + 20
    ⇒ 6x = 120

    ⇒ x =
    120
    = 20
    6