Plane Geometry


  1. Ratio of the number of sides of two regular polygons is 5 : 6 and the ratio of their each interior angle is 24 : 25. Then the number of sides of these two polygons are









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    Given , Ratio of the number of sides of two regular polygons = 5 : 6
    and the ratio of their each interior angle = 24 : 25
    Let the number of sides be 5y and 6y respectively.

    Then,
    (2 × 5y - 4) ÷ 5y
    =
    24
    (2 × 6y - 4) ÷ 6y25

    10y - 4
    5y =
    24
    12y - 4
    25
    6y

    we know that , Each interior angle =
    (2n - 4)90°
    n

    5y - 2
    ×
    6
    =
    24
    56y - 225

    Correct Option: C

    Given , Ratio of the number of sides of two regular polygons = 5 : 6
    and the ratio of their each interior angle = 24 : 25
    Let the number of sides be 5y and 6y respectively.

    Then,
    (2 × 5y - 4) ÷ 5y
    =
    24
    (2 × 6y - 4) ÷ 6y25

    10y - 4
    5y =
    24
    12y - 4
    25
    6y

    we know that , Each interior angle =
    (2n - 4)90°
    n

    5y - 2
    ×
    6
    =
    24
    56y - 225

    5y - 2
    =
    4
    6y - 25

    ⇒ 25y – 10 = 24y – 8
    ⇒ y = 10 – 8 = 2
    ∴ Number of sides = 10 and 12.


  1. Measure of each interior angle of a regular polygon can never be :









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    According to question ,
    Check through options ,

    Each interior angle =
    2n - 4
    × 90°
    n

    If measure of each angle = 105°
    then,
    (2n - 4) × 90°
    = 105°
    n

    Correct Option: B

    According to question ,
    Check through options ,

    Each interior angle =
    2n - 4
    × 90°
    n

    If measure of each angle = 105°
    then,
    (2n - 4) × 90°
    = 105°
    n

    ⇒ (2n – 4) × 6 = 7n
    ⇒ 12n – 24 = 7n
    ⇒ 5n = 24
    n =
    24
    which is impossible.
    5



  1. The sum of all interior angles of a regular polygon is twice the sum of all its exterior angles. The number of sides of the polygon is









  1. View Hint View Answer Discuss in Forum

    As we know that , Sum of interior angles = (2n – 4) × 90°
    Sum of exterior angles = 360°
    As per the given question ,
    ∴ (2n – 4) × 90° = 360° × 2
    ⇒ 2n – 4 = 2 × 360° ÷ 90 = 8
    ⇒ 2n – 4 = 8

    Correct Option: D

    As we know that , Sum of interior angles = (2n – 4) × 90°
    Sum of exterior angles = 360°
    As per the given question ,
    ∴ (2n – 4) × 90° = 360° × 2
    ⇒ 2n – 4 = 2 × 360° ÷ 90 = 8
    ⇒ 2n – 4 = 8
    ⇒ 2n = 12 ⇒ n = 6


  1. The ratio between the number of sides of two regular polygons is 1 : 2 and the ratio between their interior angles is 2 : 3. The number of sides of these polygons is respectively









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    We know that ,

    Each interior angle =
    (2n - 4) × 90°
    n

    According to question ,
    (2n - 4) × 90°
    n =
    2
    (4n - 4) × 90°
    3
    2n

    [∵ Ratio of number of sides is 1 : 2]
    (2n - 4) × 2
    =
    2
    4n - 43

    Correct Option: C

    We know that ,

    Each interior angle =
    (2n - 4) × 90°
    n

    According to question ,
    (2n - 4) × 90°
    n =
    2
    (4n - 4) × 90°
    3
    2n

    [∵ Ratio of number of sides is 1 : 2]
    (2n - 4) × 2
    =
    2
    4n - 43

    2n - 4
    =
    1
    4n - 43

    ⇒ 6n – 12 = 4n – 4
    ⇒ 6n – 4n = 12 – 4 = 8
    ⇒ 2n = 8 ⇒ n = 4
    ∴ No. of sides = 4, 8



  1. There are two regular polygons with number of sides equal to (n – 1) and (n + 2). Their exterior angles differ by 6°. The value of n is









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    According to question ,

    360°
    -
    360°
    = 6°
    (n - 1)(n + 2)

    ⇒ 360°
    n + 2 - n + 1
    = 6°
    (n - 1)(n + 2)

    Correct Option: C

    According to question ,

    360°
    -
    360°
    = 6°
    (n - 1)(n + 2)

    ⇒ 360°
    n + 2 - n + 1
    = 6°
    (n - 1)(n + 2)

    ⇒ (n – 1) (n + 2) = 180°
    n² + n – 2 = 180
    n² + n – 182° = 0
    n² + 14n – 13n – 182 = 0
    n(n + 14) – 13 (n + 14) = 0
    (n + 14) (n – 13) = 0
    n = 13, – 14 [ ∴ n ≠ –14]