Plane Geometry


  1. The sum of interior angles of a regular polygon is 1440°. The number of sides of the polygon is









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    If the number of sides of regular polygon be n, then
    The sum of interior angles of a regular polygon = 1440°
    ⇒ (2n – 4) × 90° = 1440°

    ⇒ 2n - 4 =
    1440
    = 16
    90

    ⇒ 2n – 4 = 16

    Correct Option: A

    If the number of sides of regular polygon be n, then
    The sum of interior angles of a regular polygon = 1440°
    ⇒ (2n – 4) × 90° = 1440°

    ⇒ 2n - 4 =
    1440
    = 16
    90

    ⇒ 2n – 4 = 16
    ⇒ 2n = 20
    ⇒ n = 10


  1. A polygon has 54 diagonals. The number of sides in the polygonis









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    We can find required answer with the help of given formula ,

    Number of diagonals =
    n(n - 3)
    2

    From question ,
    54 =
    n(n - 3)
    2

    Correct Option: C

    We can find required answer with the help of given formula ,

    Number of diagonals =
    n(n - 3)
    2

    From question ,
    54 =
    n(n - 3)
    2

    ⇒ n(n – 3) = 108 = 12 × 9
    ⇒ n (n – 3) = 12 ( 12 – 3)
    ⇒ n = 12
    Hence , Number of diagonals = 12



  1. Two regular polygons are such that the ratio between their number of sides is 1 : 2 and the ratio of measures of their interior angles is 3 : 4. Then the number of sides of each polygon is









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    Given , The ratio between their number of sides = 1 : 2
    and the ratio of measures of their interior angles = 3 : 4.
    As we know that ,

    Each interior angle of n –sided polygon =
    2n - 4
    right angles
    n

    According to the question,
    2 × y - 4
    y =
    3
    2 × 2y - 4
    4
    2y

    2y - 4
    ×
    2y
    =
    3
    y4y - 44

    =
    4y - 8
    = 3
    y - 1

    Correct Option: D

    Given , The ratio between their number of sides = 1 : 2
    and the ratio of measures of their interior angles = 3 : 4.
    As we know that ,

    Each interior angle of n –sided polygon =
    2n - 4
    right angles
    n

    According to the question,
    2 × y - 4
    y =
    3
    2 × 2y - 4
    4
    2y

    2y - 4
    ×
    2y
    =
    3
    y4y - 44

    =
    4y - 8
    = 3
    y - 1

    ⇒ 4y – 8 = 3y – 3
    ⇒ 4y – 3y = 8 – 3
    ⇒ y = 5
    ∴ Number of sides of polygons = 5 and 10.


  1. If an interior of a regular polygon is 170°, then the number of sides of the polygon is









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    Here , An interior of a regular polygon = 170°
    we know that ,

    Each interior angle of regular polygon =
    2n - 4
    × 90°
    n

    where, n = number of sides
    2n - 4
    × 90° = 170°
    n

    Correct Option: A

    Here , An interior of a regular polygon = 170°
    we know that ,

    Each interior angle of regular polygon =
    2n - 4
    × 90°
    n

    where, n = number of sides
    2n - 4
    × 90° = 170°
    n

    (2n - 4)
    × 9 = 17
    n

    ⇒ 18n – 36 = 17n
    ⇒ 18n – 17n = 36
    ⇒ n = 36



  1. The length of the diagonal BD of the parallelogram ABCD is 18 cm. If P and Q are the centroid of the ;∆ ABC and ∆ ADC respectively then the length of the line segment PQ is









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    According to question , we draw a figure of parallelogram ABCD ,

    Centroid is the point where medians intersect. Diagonals of parallelogram bisect each other.

    OP =
    1
    × 9 = 3cm
    3

    Correct Option: B

    According to question , we draw a figure of parallelogram ABCD ,

    Centroid is the point where medians intersect. Diagonals of parallelogram bisect each other.

    OP =
    1
    × 9 = 3cm
    3

    OQ =
    1
    × 9 = 3cm
    3

    ∴ PQ = OP + OQ = 3 + 3 = 6cm