Number System
-  The sum of three consecutive natural numbers each divisible by 5, is 225. The largest among them is
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                        View Hint View Answer Discuss in Forum Let the required largest number be x. 
 According to the question,
 x + x – 5 + x – 10 = 225
 ⇒ 3x – 15 = 225
 ⇒ 3x = 225 + 15 = 240⇒ x = 240 = 80 3 Correct Option: DLet the required largest number be x. 
 According to the question,
 x + x – 5 + x – 10 = 225
 ⇒ 3x – 15 = 225
 ⇒ 3x = 225 + 15 = 240⇒ x = 240 = 80 3 
-  The sum of three consecutive natural numbers divisible by 3 is 45. The smallest number is :
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                        View Hint View Answer Discuss in Forum Let the numbers be : 3x, 3x + 3 and 3x + 6 
 According to the question,
 3x + 3x + 3 + 3x + 6 = 45
 ⇒ 9x + 9 = 45
 ⇒ 9x = 45 – 9 = 36⇒ x = 36 = 4 9 
 ∴ The smallest number
 = 3x = 3 × 4 = 12
 Correct Option: CLet the numbers be : 3x, 3x + 3 and 3x + 6 
 According to the question,
 3x + 3x + 3 + 3x + 6 = 45
 ⇒ 9x + 9 = 45
 ⇒ 9x = 45 – 9 = 36⇒ x = 36 = 4 9 
 ∴ The smallest number
 = 3x = 3 × 4 = 12
 
-  Two positive whole numbers are such that the sum of the first number and twice the second number is 8 and their difference is 2. The numbers are :
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                        View Hint View Answer Discuss in Forum Let the numbers be x and y. 
 According to the question,
 x + 2y = 8 .... (i)
 x – y = 2 ....... (ii)
 By equation (i) – (ii),
 2y + y = 8 – 2
 ⇒ 3y = 6 ⇒ y = 2
 From equation (ii),
 x – 2 = 2 ⇒ x = 4Correct Option: CLet the numbers be x and y. 
 According to the question,
 x + 2y = 8 .... (i)
 x – y = 2 ....... (ii)
 By equation (i) – (ii),
 2y + y = 8 – 2
 ⇒ 3y = 6 ⇒ y = 2
 From equation (ii),
 x – 2 = 2 ⇒ x = 4
-  What is the arithmetic mean of first 20 odd natural numbers ?
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                        View Hint View Answer Discuss in Forum Sum of first n odd natural numbers = n2 = (20)2 = 400 Correct Option: DSum of first n odd natural numbers = n2 = (20)2 = 400 ∴ Required average = 400 = 20 20 
 
-  Find the sum of all positive multiples of 3 less than 50
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                        View Hint View Answer Discuss in Forum Sum of all multiples of 3 upto 50 
 = 3 + 6 + ..... + 48
 = 3 (1 + 2 + 3 + .... + 16)= 3 × 16(16 + 1) = 3 × 8 × 17 2 
 = 408 ∵ 1 + 2 + 3 + .....+ n = n(n + 1)  2 Correct Option: CSum of all multiples of 3 upto 50 
 = 3 + 6 + ..... + 48
 = 3 (1 + 2 + 3 + .... + 16)= 3 × 16(16 + 1) = 3 × 8 × 17 2 
 = 408 ∵ 1 + 2 + 3 + .....+ n = n(n + 1)  2 
 
	