Number System
- If 1 is added to both the numerator and the denominator of a fraction, it becomes
1/4 . If 2 is added to both the numerator and the denominator of that fraction, it becomes
1/3. The sum of numerator and denominator of the fraction is :
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x + y = 120 ....... (i)
x = 5 y
⇒ x = 5y
From, equation (i),
5y + y = 120
⇒ 6y = 120 ⇒ y = 20
∴ x = 120 – 20 = 100
∴ Difference = 100 – 20 = 80Correct Option: C
x + y = 120 ....... (i)
x = 5 y
⇒ x = 5y
From, equation (i),
5y + y = 120
⇒ 6y = 120 ⇒ y = 20
∴ x = 120 – 20 = 100
∴ Difference = 100 – 20 = 80
- A student was asked to multiply a given number by 8/17. Instead, he divided the given number by 8/17. His answer was 225 more than the correct answer. The given number was
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Here, the first divisor (91) is a multiple of second divisor (13).
∴ Required remainder = Remainder obtained on dividing 17 by 13 = 4Correct Option: B
Here, the first divisor (91) is a multiple of second divisor (13).
∴ Required remainder = Remainder obtained on dividing 17 by 13 = 4
- A girl was asked to multiply a number by 7/8 , instead she divided the number by 7/8 and got the result 15 more than the correct result. The sum of the digits of the number was :
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Of the given alternatives,
When 64 is divided by 3, remainder = 1
When 65 is divided by 5, remainder = 0Correct Option: C
Of the given alternatives,
When 64 is divided by 3, remainder = 1
When 65 is divided by 5, remainder = 0
- A fraction becomes 1/3 when 1 is subtracted from both the numerator and the denominator. The same fraction becomes 1/2 when 1 is added to both the numerator and the denominator. The sum of numerator and denominator of the fraction is
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Let the unknown number be x.
∴ 71 x + 47 = 98 × 7
⇒ 71x = 686 – 47 = 639⇒ x = 639 = 9 = 3 × 3 71 Correct Option: D
Let the unknown number be x.
∴ 71 x + 47 = 98 × 7
⇒ 71x = 686 – 47 = 639⇒ x = 639 = 9 = 3 × 3 71
- The denominator of a fraction is 3 more than its numerator. If the numerator is increased by 7 and the denominator is decreased by 2, we obtain 2. The sum of numerator and denominator of the fraction is
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461 + 462 + 463
= 461 (1 + 4 + 42)
= 461 × 21 which is divisible by 3.Correct Option: A
461 + 462 + 463
= 461 (1 + 4 + 42)
= 461 × 21 which is divisible by 3.