Number System
-  999 998 × 999 is equal to : 999 
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                        View Hint View Answer Discuss in Forum 999 998 × 999 999 =  999 998  × 999 999 
 Correct Option: A999 998 × 999 999 =  999 998  × 999 999 
 Required answer = 9992 + 998
 Required answer = (1000 – 1)2 + 998
 Required answer = 1000000 – 2000 + 1 + 998
 Required answer = 998999
-  The number which is to be added to 0.01 to get 1.1, is
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                        View Hint View Answer Discuss in Forum Let p be added to given number . 
 According to question ,
 ⇒ p + 0.01 = 1.1
 ⇒ p = 1.1 - 0.01Correct Option: BLet p be added to given number . 
 According to question ,
 ⇒ p + 0.01 = 1.1
 ⇒ p = 1.1 - 0.01
 ∴ Required number = 1.1 – 0.01 = 1.09
-  If [n] denotes the greatest integer < n and (n) denotes the smallest integer > n, where n is any real number, then 1 1  ×  1 1  −  1 1  ÷  1 1  + (1.5) is 5 5 5 5 
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                        View Hint View Answer Discuss in Forum [n] < n (integer); (n) > n (integer) 
 ∴ Expression 1 1  ×  1 1  −  1 1  ÷  1 1  + (1.5) = 2 × 1 – 2 ÷ 1 + 2 5 5 5 5 Correct Option: B[n] < n (integer); (n) > n (integer) 
 ∴ Expression 1 1  ×  1 1  −  1 1  ÷  1 1  + (1.5) = 2 × 1 – 2 ÷ 1 + 2 = 2 5 5 5 5 
-  Which one of the following will completely divide 571 + 572 + 573 ?
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                        View Hint View Answer Discuss in Forum 571 + 572 + 573 = 571 (1 + 5 + 52) Correct Option: C571 + 572 + 573 = 571 (1 + 5 + 52) 
 ⇒ 571 + 572 + ⇒ 573 = 571 × which is exactly divisible by 155.
 Hence required answer is 155 .
-  The smallest number that must be added to 803642 in order to obtain a multiple of 11 is
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                        View Hint View Answer Discuss in Forum  
 ∴ The required number = 11 – 4 = 7
 2nd Method to solve this question :
 Sum of digits at odd places = 2 + 6 + 0 = 8Correct Option: C 
 ∴ The required number = 11 – 4 = 7
 2nd Method to solve this question :
 Sum of digits at odd places = 2 + 6 + 0 = 8, sum of digits at even places = 4 + 3 + 8 = 15. For divisibility by 11, difference i.e., (15 – 8) = 0 or mutiple of 11.
 ∴ The required number = 7
 
	