191. 7, 77, 77, 777 ÷ 77 equals

1. 1. 1111

   
   
   

   2. 101001

   
   
   

   3. 10101

   
   
   

   4. 1010101

   
   
   

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1. View Hint View Answer Discuss in Forum

   77777777 ÷ 77 = 1010101

   Correct Option: D

   77777777 ÷ 77 = 1010101

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192. 8.31 + 0.6 + 0.002 is equal to

1. 1. 8.912

   
   
   

   2. 8.912

   
   
   

   3. 8.979

   
   
   

   4. 0.86

   
   
   

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1. View Hint View Answer Discuss in Forum

   Expression
   = 8.31 + 0.6 + 0.002
   
   

   Correct Option: C

   Expression
   = 8.31 + 0.6 + 0.002
   
   

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193. Numbers 2, 4, 6, 8, 10, ....., 196, 198, 200 are multiplied together. The number of zeros at the end of the product on the right will be equal to —

1. 1. 21

   
   
   

   2. 22

   
   
   

   3. 24

   
   
   

   4. 25

   
   
   

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1. View Hint View Answer Discuss in Forum

   When we multiply 2 and 5 (at unit place) we get a zero
   ∴  Number of zeros = The number of zeros in the end in the
   product of 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190
   and 200 = 24

   Correct Option: C

   When we multiply 2 and 5 (at unit place) we get a zero
   ∴  Number of zeros = The number of zeros in the end in the
   product of 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190
   and 200 = 24

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194. 2.8768 is equal to

1. 1. 2	4394
      	4995

   
   
   

   2. 2	292
      	333

   
   
   

   3. 2	9
      	10

      
      (4)

   
   
   

   4. 2	878
      	999

   
   
   

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1. View Hint View Answer Discuss in Forum

   2.8768 = 2	8768 − 8
   	9990

   
   

   = 2	8760	= 2	292
   	9990		333

   Correct Option: B

   2.8768 = 2	8768 − 8
   	9990

   
   

   = 2	8760	= 2	292
   	9990		333

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195. When simplified the product
     

     	1 −	1			1 −	1			1 −	1		........		1 −	1
     		3				4				5					n

     
     it becomes :

1. 1. 1

      n

   
   
   

   2. 1

      n

      
      

   
   
   

   3. 2(n − 1)

      n

   
   
   

   4. 2

      n(n + 1)

   
   
   

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1. View Hint View Answer Discuss in Forum

   	1 −	1			1 −	1			1 −	1		........		1 −	1
   		3				4				5					n

   
   

   =	2	×	3	×	4	×......×	n − 1	=	2
   	3		4		5		n		n

   
   We observe that denominator of a term cancels with the numerator of the succeeding term
   

   Correct Option: B

   	1 −	1			1 −	1			1 −	1		........		1 −	1
   		3				4				5					n

   
   

   =	2	×	3	×	4	×......×	n − 1	=	2
   	3		4		5		n		n

   
   We observe that denominator of a term cancels with the numerator of the succeeding term
   

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