Number System
-  Find the greatest number of 4 digits and the least number of 5 digits which when divided by 789 leave a remainder 5 in each case.
- 
                        View Hint View Answer Discuss in Forum The greatest number of 4 digits = 9999 
 Now, we divide 9999 by 789 
 Thus, when 9999 – 531= 9468 is divided by 789, no remainder is left.
 The required greatest number of
 4 digits = 9468 + 5 = 9473
 The least number of 5 digits
 = 10000 
 Remainder = 532
 ∴ The least number of 5 digits exactly divisible by 789
 = 10000 + (789 – 532)
 = 10000 + 257 = 10257
 ∴ The required number
 = 10257 + 5 = 10262
 Remark : If 532 is subtracted from 10000 the number obtained 9468 is exactly divisible by 789 but in that case, the number will not be of 5 digits but of 4 digits.Correct Option: AThe greatest number of 4 digits = 9999 
 Now, we divide 9999 by 789 
 Thus, when 9999 – 531= 9468 is divided by 789, no remainder is left.
 The required greatest number of
 4 digits = 9468 + 5 = 9473
 The least number of 5 digits
 = 10000 
 Remainder = 532
 ∴ The least number of 5 digits exactly divisible by 789
 = 10000 + (789 – 532)
 = 10000 + 257 = 10257
 ∴ The required number
 = 10257 + 5 = 10262
 Remark : If 532 is subtracted from 10000 the number obtained 9468 is exactly divisible by 789 but in that case, the number will not be of 5 digits but of 4 digits.
-  Find the number nearest to 12199 which is exactly divisible by the product of the first four
 prime numbers.
- 
                        View Hint View Answer Discuss in Forum As we know, the first four prime numbers are 2, 3, 5, 7 
 Their product = 2 × 3 × 5 × 7 = 210
 Now, we divide 12199 by 210 
 Here, D – R = 210 – 19 = 191
 So, (D – R) > R.
 Hence, the required number
 = 12199 – R = 12199 – 19
 = 12180Correct Option: DAs we know, the first four prime numbers are 2, 3, 5, 7 
 Their product = 2 × 3 × 5 × 7 = 210
 Now, we divide 12199 by 210 
 Here, D – R = 210 – 19 = 191
 So, (D – R) > R.
 Hence, the required number
 = 12199 – R = 12199 – 19
 = 12180
-  Find the number nearest to 77685 which is exactly divisible by 720.
- 
                        View Hint View Answer Discuss in Forum We divide 77685 by 720  
 Here, D – R = 720 – 645 = 75 < R.
 ∴ The required number
 = 77685 + 75 = 77760Correct Option: CWe divide 77685 by 720  
 Here, D – R = 720 – 645 = 75 < R.
 ∴ The required number
 = 77685 + 75 = 77760
-  Find the nearest number to 56586 which is exactly divisible by 552.
- 
                        View Hint View Answer Discuss in Forum We divide 56586 by 552  
 ∴ R = 282
 D = 552
 ∴ D – R = 552 – 282 = 270
 Here, (D – R) < R
 So, we get the required number
 by adding (D – R) to the dividend.
 Therefore, the number nearest to 56586 that is exactly divisible by 552 is
 56586 + 270 = 56856Correct Option: BWe divide 56586 by 552  
 ∴ R = 282
 D = 552
 ∴ D – R = 552 – 282 = 270
 Here, (D – R) < R
 So, we get the required number
 by adding (D – R) to the dividend.
 Therefore, the number nearest to 56586 that is exactly divisible by 552 is
 56586 + 270 = 56856
-  Find the least number of five digits which is divisible by 666.
- 
                        View Hint View Answer Discuss in Forum The least number of five digits = 10000 
 Now, we divide 10000 by 666 
 Here, we have 10 as remainder.
 Therefore, the least number to be added to the least number of 5 digits, i.e., 10000 to get the least number of 5 digits which is exactly divisible by 666 is 666– 10 or 656.
 Hence, the required number
 = 10000 + 656 = 10656.Correct Option: AThe least number of five digits = 10000 
 Now, we divide 10000 by 666 
 Here, we have 10 as remainder.
 Therefore, the least number to be added to the least number of 5 digits, i.e., 10000 to get the least number of 5 digits which is exactly divisible by 666 is 666– 10 or 656.
 Hence, the required number
 = 10000 + 656 = 10656.
 
	