Number System
-  In a school 1/10 of the boys are same in number as 1/4 of the girls and 5/8 of the girls are same in number as 1/4 of the boys. The ratio of the boys to girls in that school is
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                        View Hint View Answer Discuss in Forum Required Number 
 = 100x + 10y + z
 ∵ 10y + z = 6m
 ∴ Number = 100x + 6m, where m is a positive integer.
 = 2 (50x + 3m)Correct Option: CRequired Number 
 = 100x + 10y + z
 ∵ 10y + z = 6m
 ∴ Number = 100x + 6m, where m is a positive integer.
 = 2 (50x + 3m)
-  A, B, C and D purchase a gift worth ₹ 60. A pays 1/2 of what others are paying, B pays
 1/3 of what others are paying and C pays 1/4 of what others are paying. What is the amount paid by D ?
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                        View Hint View Answer Discuss in Forum (x – 2) is a factor of polynomial P (x) = x3 + x2 – 5x + λ. 
 ∴ P(2) = 0 (i.e., on putting x = 2)
 ⇒ 23 + 22 – 5 × 2 + λ = 0
 ⇒ 8 + 4 – 10 + λ = 0
 ⇒ λ + 2 = 0
 ⇒ λ = –2Correct Option: B(x – 2) is a factor of polynomial P (x) = x3 + x2 – 5x + λ. 
 ∴ P(2) = 0 (i.e., on putting x = 2)
 ⇒ 23 + 22 – 5 × 2 + λ = 0
 ⇒ 8 + 4 – 10 + λ = 0
 ⇒ λ + 2 = 0
 ⇒ λ = –2
-  In an office, there are 108 tables and 132 chairs. If 1/6 of the tables and 1/4 of the chairs are broken. How many people can work in the office if each person requires one
 table and one chair?
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                        View Hint View Answer Discuss in Forum We have to find such numbers which are divisible by 12 (LCM of 4 and 6). 
 Number of numbers divisible by 12 and lying between 1 to 600= 600 − 1 = 49 12 
 Number of numbers divisible by12 from 1 to 100 = 100 = 8 12 
 ∴ Required answer
 = 49 – 8 = 41Correct Option: CWe have to find such numbers which are divisible by 12 (LCM of 4 and 6). 
 Number of numbers divisible by 12 and lying between 1 to 600= 600 − 1 = 49 12 
 Number of numbers divisible by12 from 1 to 100 = 100 = 8 12 
 ∴ Required answer
 = 49 – 8 = 41
-  A person gives 1/4 of his property to his daughter, 1/2 to his sons and 1/5 for charity. How much has he given away ?
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                        View Hint View Answer Discuss in Forum Here, first divisor (175) is a multiple of second divisor (25). 
 ∴ Required remainder = Remainder obtained on dividing 132 by 25 = 7Correct Option: BHere, first divisor (175) is a multiple of second divisor (25). 
 ∴ Required remainder = Remainder obtained on dividing 132 by 25 = 7
-  A number whose one-fifth part increased by 4 is equal to its one-fourth part diminished by 10, is :
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                        View Hint View Answer Discuss in Forum Here, 280 is a multiple of 35. 
 ∴ Required remainder
 = Remainder obtained on dividing 115 by 35 = 10Correct Option: BHere, 280 is a multiple of 35. 
 ∴ Required remainder
 = Remainder obtained on dividing 115 by 35 = 10
 
	