The sum of three consecutive natural numbers divisible by

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The sum of three consecutive natural numbers divisible by 3 is 45. The smallest number is :

Let the numbers be : 3x, 3x + 3 and 3x + 6
According to the question,
3x + 3x + 3 + 3x + 6 = 45
⇒ 9x + 9 = 45
⇒ 9x = 45 – 9 = 36

⇒ x =	36	= 4
	9

∴ The smallest number
= 3x = 3 × 4 = 12